Question

a coin press creates a pressure of 3.20*10^8 Pa on a nickel of radius 0.0106 m. how much force does the press exert on the coin?(unit=N) PLEASE HELPPPPPPPPPPPPPP

Answer 1

Answer:

1.13 x 10⁵N

Explanation:

Given parameters:

Pressure of the coin press = 3.2 x 10⁸ Pa

radius of the nickel coin = 0.0106m

Unknown:

Force of the press on coil = ?

Solution:

Our knowledge of pressure will help us solve this problem.

Pressure is defined as the force applied per unit area on a body.

              Pressure  = $\frac{force}{area}$

  Force = Pressure  x  Area

 Since the pressure is known;

Area of the coin = Area of a circle = π r²

 where r is the radius of the coin;

Area of the coin = π x 0.0106²  = 3.53 x 10⁻⁴m²

  Force = 3.2 x 10⁸ x  3.53 x 10⁻⁴  = 1.13 x 10⁵N