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3 years ago

Question 15 When moving oxidation numbers down as subscripts in an ionic bond, do you include the charge (+/-)?

Physics

1 answer:

m_a_m_a [10]3 years ago

5 0

Answer:

C)No

Explanation:

When moving oxidation numbers down as subscripts in an ionic bond, you do not include the charge either positive or negative.

The process of moving oxidation number down as subscript is known as exchange of valency.

The combining power is used in exchanging valency and this is oxidation number exchanged. The number corresponds to the number of electrons usually lost or gained or shared by atoms of elements during chemical combination or the number of positive or negative charges carried by ions.

The combining power is exchanged as simple whole number ratio during the formation of chemical formulae of compounds.

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Signal far enough ahead so other drivers in your vicinity can make adjustments to your change in speed and ___________.

3241004551 [841]

Answer:

DIRECTION

Explanation:

the answer of the blank will be DIRECTION

As the signal is far ahead so driver can make the decision of what he have to do either he can change direction or he can be on his same path.

But for that driver has to change his or her speed.

so, from the statement given the blank will be filled with DIRECTION

8 0

3 years ago

A 0.12 g honeybee acquires a charge of +24pC while flying. The earth's electric field near the surface is typically 100 N/C, dow

shusha [124]

Answer:

150000000

$\dfrac{F_e}{F_g}=0.00000203873598369$

49050000 N/C

Explanation:

q = Charge = 24 pC

m = Mass of honeybee = 0.12 g

E = Electric field = 100 N/C

g = Acceleration due to gravity = 9.81 m/s²

$1\ C=6.25\times 10^{18}\ electrons$

Number electrons is

$n=24\times 10^{-12}\times 6.25\times 10^{18}\\\Rightarrow n=150000000$

The number of electrons added or removed was 150000000

Force is given by

$F_e=Eq\\\Rightarrow F_e=100\times 24\times 10^{-12}\\\Rightarrow F_e=2.4\times 10^{-9}\ N$

The ratio is

$\dfrac{F_e}{F_g}=\dfrac{2.4\times 10^{-9}}{0.12\times 10^{-3}\times 9.81}\\\Rightarrow \dfrac{F_e}{F_g}=0.00000203873598369$

The ratio is $\dfrac{F_e}{F_g}=0.00000203873598369$

Balancing the forces we get

$Eq=mg\\\Rightarrow E=\dfrac{mg}{q}\\\Rightarrow E=\dfrac{0.12\times 10^{-3}\times 9.81}{24\times 10^{-12}}\\\Rightarrow E=49050000\ N/C$

The electric field required is 49050000 N/C

4 0

3 years ago

Which is an example of a physical change

cupoosta [38]

Answer:

ice forming and then melting back into water

4 0

3 years ago

A 1210 kg rollercoaster car is

ratelena [41]

Answer: 4.98 m/s

Explanation:

You solve these kinetic energy, potential energy problems by using the fact P.E.+ K.E. = a constant as long as friction is ignored.

PEi = 0 in this case

KEi = ½mVi² = PEf+KEf = mghf + ½mVf²

½1210*8.31² = 1210*9.8*2.26 + ½1210*Vf²

½1210*Vf² = ½1210*8.31² - 1210*9.8*2.26

Vf² = 8.31² - 2*9.8*2.26 = 4.98² so Vf = 4.98m/s

3 0

3 years ago

What is the reaction force of the table with a weight of 558N

Delicious77 [7]

Answer: reaction force = -558N

Explanation:

w = f = 558N

since action force and reaction force are equal in magnitude and opposite in direction,

reaction force = -(f)

reaction force = -558N

if that helps.

8 0

3 years ago