Which property of light waves is responsible for what we see as brightness or intensity?

1 answer:

8 0

Electromagnetic radiation is one of many ways as energy travels through space.
As you may already know, a wave has a valley (lowest point) and a ridge (highest point). The vertical distance between the tip of the crest and the central axis of the wave is known as amplitude. This is the property associated with the brightness, or intensity, of the wave. The horizontal distance between two consecutive crests or valleys of the wave is known as wavelength

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How fast, in rpm, would a 5.6 kg, 25-cm-diameter bowling ball have to spin to have an angular momentum of 0.26 kgm2/s

solong [7]

Answer:

71 rpm

Explanation:

Given that:

Angular momentum (L) = 0.26

Diameter = 25cm = 0.25 cm

Radius, r = (d/2) = 0.125m

Mass = 5.6 kg

Moment of inertia (I) = 2mr² / 5

I = (2 * 5.6 * 0.125^2) / 5

= 0.175

= 0.175 / 5

= 0.035 kgm²

Angular speed (w) ;

w = L / I

w = 0.26 / 0.035

= 7.4285714

= 7.429 rad/s

w = (7.429 * 60/2π)

w = 445.74 / 2π rpm

w = 70.941724

Angular speed = 70.94 rpm

= 71 rpm

5 0

3 years ago

Define wavelength as it relates to the electromagnetic spectrum.

swat32

The electromagnetic spectrum is traditionally divided into regions of radio waves, microwaves, infrared radiation, visible light, ultraviolet rays, x rays, and gamma rays. ... Wavelength defines the distance between adjacent points of the electromagnetic wave that are in equal phase (e.g., wavecrests)

7 0

3 years ago

Read 2 more answers

2. Below what depth would a submarine have to submerge so that it would not be swayed by surface waves with a wavelength of 24 m

Travka [436]

<u>Answer:</u> Below 12m of depth, the submarine has to submerge so that it would not be swayed by surface waves

<u>Explanation:</u>

To avoid the surface waves, a submarine has to submerge below the wave base. It is the position below which the motion of the waves is negligible.

This wave base is equal to half of the wavelength. The equation becomes:

Wave base = $\frac{\text{Wavelength}}{2}$