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3 years ago

PLEASE NEED HELP NOW!11 50 POINTS AND BRAINLY!!!!!!

Physics

2 answers:

Vilka [71]3 years ago

6 0

You know that you need to show the ven diagram and the topics of it.

Tamiku [17]3 years ago

6 0

For the first one

Compounds
Chemically combinedFixed proportionsComponents change properties

BothMade of elements2 or more components

MixturesPhysically combinedVariable proportionsComponents retain properties

For the second one.

Will accelerate to the leftA box experiences a 20 N force to the left and two different 8 N forces to the right

A box experiences a 20 N force to the left and a 19 N frictional force to the right

Will accelerate to the right

A rope experiences three 400 N forces to the left and three different 410 N forces to the right

A skateboard is pushed up a hill with a 90 N force to the left and experiences a gravitational force of 100 N to the right

A bottle rocket experiences a 500 N force to the right and 300 N of air resistance to the left

A car experiences a 300 N force to the right from the engine and separate 150 N force due to friction and air resistance to the left.

And none for will not accelerate

For the third one

A fireman turns on his hose and is knocked backwards.3rd Law

It takes less force to move a ping pong ball than a bowling ball.2nd Law

A soccer ball will not move until a player kicks it.1st law

If air lets out of a balloon quickly, it pushes down and the balloon moves up.3rd Law

F = ma2nd Law

A bowling ball hits the pins and they fly off in all directions.1st Law

Hope this helps!

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3. What methods are you using to test this (or each) hypothesis?.

Gnoma [55]

Answer:

my method is guessing it works 50% of the time :)

Explanation:

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3 years ago

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Calculate the distance travel if it accelerates from 0 to 27.8 meters per second in 2.5 seconds

luda_lava [24]

The distance travel is 69.5 meters.

Explanation:

Given datas are as follows

Speed = 27.8 meters / second

Time = 2.5 seconds

The formula to calculate the speed using distance and time is

Speed = Distance ÷ Time (units)

Then Distance = Speed × Time (units)

Distance = (27.8 × 2.5) meters

Distance = 69.50 meters

Therefore the distance travelled is 69.50 meters.

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3 years ago

What are some guidelines for using self-assessments?

lakkis [162]

Decide which components you wish to assess yourself. There is no set order in which you do this. you could, for an example assess one or two elements and skip the rest.

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2 years ago

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You stand17.5 m from a wall holding a baseball. You throw the baseball at the wall at an angle of 20.5∘ from the ground with an

Lelechka [254]

Answer: 8.8 m

Explanation:

The movement of the baseball to the wall is a example of parabolic motion. While the baseball aproach the wall it is affected by gravity.

In this case, because the Initial Velocity of the ball is a vecotr, it can be defined using its two directionals compounds. One, on the Y-axis and another on the X-axis. This can be related, on how a hypotenuse is the product of two legs of the triangle. Because of this, each one of this, can be know using the following equation:

Vx = Vo * cos(∅)

Vy = Vo * sin(∅)

Where Vo is the initial velocity 27.5 m/s, and ∅ is the angle which is 20.5°. So we calculate:

Vx = 27.5m/s * cos(20.5)

Vx = 27.5m/s * 0.936

Vx = 25.74m/s

Vy = 27.5m/s * sin(20.5)

Vy = 9.62m/s

Now the movement is divided on two parts, one under the effect of gravity and another one with a constant velocity.

To know how tall does the baseball hit the wall, we need to know first how much time it takes the ball to reach the wall on the X-axis. The wall is 17.5m away, we velocity on Vx that is constant we can calculate as it follow:

Time (T) = Distance (D) / Velocity (V)

Where Distance is 17.5m and our Velocity is the Vx calculated before.

T = 17.5 m / 25.74m/s

T = 0.68s

This is the time it takes the ball to reach the wall.

Know with the time, we can calculate the how tall it got on that time with the following equation:

$x = (Vo*t) + (\frac{1}{2} *a*t^{2} )$

Where Vo is the Y-Compound of the Initial Velocity.

a is the aceleration, in this case the Gravity. Which, will be negative because is oposing the movement. Gravity is equal to 9.81 $m/s^{2}$

And t is the time it takes the ball to get to the wall.

$x = (Vy*T) + (\frac{1}{2} *g*T^{2} )$

$x = ((9.62m/s)*0.68s) + (\frac{1}{2} *(9.81m/s^{2})*(0.68s)^{2} )$

$x = 8.8 m$

This is the height that the baseball touch the wall.

6 0

3 years ago

What is the wavelength of an earthquake that shakes you with a frequency of 10.0 Hz and gets to another city 84.0 km away in 12.

Harrizon [31]

Answer:

700 m.

Explanation:

Wavelength: This can be defined as the distance in meter required by a wave to complete one oscillation. The S.I unit of of wavelength is meter (m).

the expression connecting velocity, frequency and wavelength is given as,

v = λf......................... Equation 1

Where v = velocity of the earthquake, λ = wavelength of the earthquake, f = frequency of the earthquake.

make λ the subject of the equation

λ = v/f ................. Equation 2

recall,

v = distance/time

v = d/t ................. Equation 2

Where d = distance, t -= time.

Given: d = 84 km = 84000 m, t = 12 s.

Substitute into equation 2

v = 84000/12

v = 7000 m/s.

Also given: f = 10 Hz.

Substitute into equation 2

λ = 7000/10

λ = 700 m.

Hence the wavelength of the earthquake = 700 m.

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3 years ago

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