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3 years ago

PLEASE NEED HELP NOW!11 50 POINTS AND BRAINLY!!!!!!

Physics

2 answers:

Vilka [71]3 years ago

6 0

You know that you need to show the ven diagram and the topics of it.

Tamiku [17]3 years ago

6 0

For the first one

Compounds
Chemically combinedFixed proportionsComponents change properties

BothMade of elements2 or more components

MixturesPhysically combinedVariable proportionsComponents retain properties

For the second one.

Will accelerate to the leftA box experiences a 20 N force to the left and two different 8 N forces to the right

A box experiences a 20 N force to the left and a 19 N frictional force to the right

Will accelerate to the right

A rope experiences three 400 N forces to the left and three different 410 N forces to the right

A skateboard is pushed up a hill with a 90 N force to the left and experiences a gravitational force of 100 N to the right

A bottle rocket experiences a 500 N force to the right and 300 N of air resistance to the left

A car experiences a 300 N force to the right from the engine and separate 150 N force due to friction and air resistance to the left.

And none for will not accelerate

For the third one

A fireman turns on his hose and is knocked backwards.3rd Law

It takes less force to move a ping pong ball than a bowling ball.2nd Law

A soccer ball will not move until a player kicks it.1st law

If air lets out of a balloon quickly, it pushes down and the balloon moves up.3rd Law

F = ma2nd Law

A bowling ball hits the pins and they fly off in all directions.1st Law

Hope this helps!

You might be interested in

If an object's kinetic energy is zero, what is its momentum?

hammer [34]

If the object's kinetic energy is zero, then due to in multiplication factor, it's momentum will also be equal to zero 'cause the velocity of the object must be Nil

In short, Your Answer would be: "Zero"

Hope this helps!

6 0

3 years ago

To demonstrate the tremendous acceleration of a top fuel dragracer, you attempt to run your car into the back of a dragster that

noname [10]

Answer:

a. 2v₀/a b. 2v₀/a

Explanation:

a. Since you are moving with a constant velocity v₀, the distance, s you cover in time = t max is s = v₀t.

Since the dragster starts from rest with an acceleration, a, using

s' = ut + 1/2at² where u = 0 and s' = distance moved by dragster

s' = 0t + 1/2at²

s' = 1/2at²

Since the distance moved by me and the dragster must be the same,

s = s'

v₀t. = 1/2at²

v₀t. - 1/2at² = 0

t(v₀ - 1/2at) = 0

t= 0 or v₀ - 1/2at = 0

t= 0 or v₀ = 1/2at

t= 0 or t = 2v₀/a

So the maximum time tmax = 2v₀/a

b. Since the distance covered by me to meet the dragster is s = v₀t in time, t = tmax which is also my distance from the dragster when it started. So, my distance from the dragster when it started is s = v₀(2v₀/a)

= 2v₀/a

4 0

3 years ago

Cloudy nights are usually warm because

almond37 [142]

Answer:

When you have a cloudy night, the clouds prevent heat from escaping through the atmosphere and into space.

The clouds act like a blanket and trap the heat it, and that is why every time you have a cloudy night, it is always warmer than a clear night.

5 0

2 years ago

A basketball player makes a bounce pass by throwing the ball with a speed of 5.3 m/s and at an angle 12° below the horizontal. I

Dima020 [189]

Answer:

ball hit the ground from her feet is 1.83 m far away

Explanation:

given data

speed = 5.3 m/s

angle = 12°

height = 1 m

to find out

how far from her feet ball hit ground

solution

we consider here x is horizontal component and y is vertical component

so in vertical

velocity will be = v sin12

vertical speed u = 5.3 sin 12 = 1.1 m/s downward

and

in horizontal , velocity we know v = 5.3 m/s

so from motion of equation

s = ut + 0.5×a×t²

s is distance t is time a is 9.8

put all value

1 = 1.1 ( t) + 0.5×9.8×t²

solve it we get t

t = 0.353 s

and

horizontal distance is = vcos12 × t

so horizontal distance = 5.3×cos12 × ( 0.353)

horizontal distance = 1.83 m

so ball hit the ground from her feet is 1.83 m far away

5 0

3 years ago

James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.

belka [17]

a. The most momentum is attained by James.

b. The resultant force acting on her is 90.77N.

c. Time taken for him to stop is 3.24 s

<h3>What is momentum?</h3>

Momentum of any object is the product of the velocity of the object and its mass.

P =mv

James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.

Substitute the values, we get

P jane= 98 kg x 3

P jane= 294 kg.m/s

Momentum of Basma, is

P Basma = 59 kg x 4

P Basma = 236 kg.m/s

Therefore, the momentum is large for James.

b. Basma approaches a road, so she stops quickly. It takes her 2.6 seconds to stop. The resultant force acting on her

F. t = P Basma

F =[ 236/2.6

F = 90.77 N

Thus, the resultant force on Basma is 90.77 N.

c. James also stops for the road. If he were to have the same resultant force acting on him, Time taken for him to stop is

F = 90.77 = P james/t

t = 294 / 90.77

t = 3.24 s

Thus, time taken for James to stop for the same resultant force is 3.24 s

Learn more about momentum.

brainly.com/question/4956182

#SPJ1

5 0

2 years ago