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Oksanka [162]
3 years ago
12

Tawny notices that Jim has been forgetting to check two forms of

Physics
1 answer:
juin [17]3 years ago
6 0
I think the answer is c but I’m not sure
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Help pls, i literally so confused.
jeka94
A. Golf ball because it has the most mass and will travel faster when felling
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3 years ago
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Your fitness tracker tells you that you have delivered 124 kJ of work during your workout. The tracker also shows that you have
REY [17]

To solve this problem, we must basically count the total energy lost converting all the values given in the international system.

The energy loss is given by both 124KJ and 124food heats.

Since the energy conversion we know that 1 food calories is equal to 4,184J. So:

124 calories (\frac{4.184J}{1 calories}) = 518.816J = 0.518816kJ

Therefore the total energy lost will be

E_{lost} = 124 KJ + 0.518816 KJ

E_{lost} = 124.518KJ

Therefore the total energy lost to the surroindings in form of heat is 124.518kJ

3 0
3 years ago
A clothes dryer uses about 30 amps of current from a 240 volt line. How much power does it use?
Aneli [31]
Not sure if this answer is write or wrong but i think its <span>4500 watts

</span>
8 0
3 years ago
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A capacitor with capacitance (c) = 4.50 μf is connected to a 12.0 v battery. what is the magnitude of the charge on each of the
svet-max [94.6K]

<u>Answer:</u> The charge on each plates is 54\mu C .

<u>Explanation:</u>

The magnitude of charge that flows through the plates is directly dependent on the capacitance and the voltage flowing through the plates.

Mathematically,

Q=CV

where,

Q = charge flowing = ? C

C = capacitance = 4.5\mu F=4.5\times 10^{-6}F    (Conversion Factor: 1\mu F=10^{-6}F)

V = Voltage across the plates = 12 V

Putting values in above equation, we get:

Q=4.5\times 10^{-6}F\times 12V=54\times 10^{-6}C=54\mu C

Hence, the charge on each plates is 54\mu C .

8 0
4 years ago
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A glass slab of density 2500kg/m3 measures 20cmx10cmx50cm what is maximum pressure​
Vilka [71]

Answer:

A =150

I think it will help you bro

8 0
2 years ago
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