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inn [45]
3 years ago
13

What are the solution(s) to the quadratic equation 40 − x2 = 0? x = ±2 x = ±4 x = ±2 x = ±4

Mathematics
2 answers:
Alexandra [31]3 years ago
8 0

Answer: x=\±2\sqrt{10}

Step-by-step explanation:

To find the solutions of the quadratic equation given in the problem, you can apply the proccedure shown below:

- Subtract 40 from both sides of the equation.

- Multiply both sides of the equation by -1

- Apply square root to both sides of the equation.

Therefore, by applyin the steps above, you obtain:

40-x^2-40=0-40\\-x^2=-40\\(-1)(-x^2)=(-40)(-1)\\\\x^2=40\\\\\sqrt{x^2}=\±\sqrt{40}\\\\x=\±2\sqrt{10}

kkurt [141]3 years ago
5 0

Answer:

answer=a edg 2020

Step-by-step explanation:

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Step-by-step explanation:


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2 years ago
Find the 5th term of the expansion of ( 6x + 6y)^11
Elodia [21]

The 5 th term of the given expression is 330(6x)^{7}( 6y)^{4}.

Step-by-step explanation:

Given,

(6x+6y)^{11}

To find the 5th term of the given expression.

Formula

In a binomial series (a+b)^{n}, the r th term is = nC(r-1) a^{n-r-1} b^{r-1}, where,

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