Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.
Answer:
begins in the mouth(ptyalin converting carbohydrate to maltose), stops in the illeum (secretion of amylase) and Is completed in the body cells(to release energy)
I think it’s m(C6H12O6) = 856 g
M(C6H12O6) = 12*6+1*12+16*6 = 180 g/mol
n(C6H12O6) = m/M = 856 g / 180 g/mol = 4.756 mol
n(CO2) = 6*4.756 = 28.536 mol
M(CO2) = 12+16*2 = 44 g/mol
m(CO2) = n*M = 28.536mol*44g/mol = 1255.584 g
<h2>Phylum Anthophyta</h2>
Explanation:
Phylum Anthophyta is the phylum of flowering plants.
Bryophytes are group of seedless non-vascular plant.They are called the amphibians of plant kingdom because to complete their life cycle, they need both water and land.
Anthophyta are dominant group than the bryophyta because:
- They have a well developed vascular system.
- They have their seeds enclosed within fruits and protective sed coat that keep them viable for a long time.
Answer:
C - ao desenvolvimento de ovos depositados por borboletas.
Explanation:
Antes de responder a sua pergunta, eu preciso te explicar que esse não é o servidor brasileiro e sim o servidor dos EUA, você deve ter percebido que toda a linguagem do site esta em inglês. Isso significa que você só deve postar perguntas em português no campo "World Languagens" mesmo que a sua pergunta seja de biologia como essa. Caso você não faça isso, a sua pergunta pdoe ser excluída, sem ser respondida.
As lagartas que surgem nas espigas de milho, são resultado do ciclo de vida da lagarta e refere-se ao momento em que os ovos depositados nas plantas de milho pelas borboletas se chocam, liberando as lagartas, que se desenvolverão e virarão novas borboletas.
É impossivel que um grão e milho vire uma lagarta, ou que o sabubo apodrecido pode gerar lagartas. Além disso, o ´processo de geração espontanea é uma teoria cientifica invalida e que não deve ser considerada.
