To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
Answer:
Step-by-step explanation:
14 + 5t > = 49 (thats a greater then or equal sign)
5t > = 49 - 14
5t > = 35
t > = 35/5
t > = 7 <===
Answer:
Input is the number you feed into the expression , and the output is what you get when the calculations are finished
IT WOULD LOOK LIKE A HOUSE OF THE KING
THE SCHOOL FEES SHOULD BE CHEAP THAT EVERYONE CAN READ AT THAT SCHOOL
THAT SCHOOL SHOULD MAKE HOMEFOODS IN THIER OWN SCHOOL AND GIVE THEM TO THEIR STUDENTS WHICH WILL MAKE ALL OF THEM HEALTHY
