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Anton [14]
3 years ago
8

Find the missing number so that the equation has no solutions. 3x - 16 = _x + 15

Mathematics
1 answer:
krok68 [10]3 years ago
6 0

Answer:

3x=16

×=3.5

3.5+15=18.5

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Stella [2.4K]
The greatest common factor is 2
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About how many molecules of water are in a swimming pool that holds 200 m^3 of water ? Write your answer in scientific notation
ddd [48]
<span>metric is very conveinient
1gram=1cm^3 of water
1m^3=1,000,000,000 grams

water is 18.015 grams per mole
(1,000,000 grams water)/(18.015 grams/mole) = 55509.3 moles

there are 6.02e23 molecules in 1 mole of water so
55509.3 moles * (6.0221E23) = 3.3428E27 molecules of water </span>in 1m^3 of water
so we have200 of those
200 times <span>3.3428E27=6.6856E29 molecules

answer is </span><span>6.6856 times 10^29 mlecules</span>
4 0
4 years ago
PLZ ANSWER !!!!!!
erastova [34]

Answer:

289.877 ft

Step-by-step explanation:

You can draw the eagle and mouse by using a right triangle. You know that the height of the triangle will be 280 feet and the distance between eagle and mouse should be the hypotenuse. Since we know the angle and one side of the triangle, we can use trignometry (cosine(angle)=adjacent/hypotenuse). Plug in your values and solve for the hypotenuse.

5 0
3 years ago
I AM BEGGING, PLEASE HELP ME. CAN SOMEONE PLEASE HELP ME!
Temka [501]

Answer:

37.5

Step-by-step explanation:

180-75 = 105

180 is the sum of all the angle in a triangle

180-105 = 75

75/2 = x becuz the triangle is icoceles

=37/5

Hope this helps :) Giving me brainiest would help a lot :))

8 0
3 years ago
1/2x^2 + 4x - 1 = 0<br> How to factor it
LenaWriter [7]

Answer:

x + 4 - 3√2 and x + 4 + 3√2

Step-by-step explanation:

When other methods seem to difficult to apply, try using the quadratic formula:

Here a = 1/2, b = 4 and c = -1.

Then the "discriminant" is b^2 - 4ac, or

(4)^2 - 4(1/2)(-1), or 16 + 2 = 18

Then the roots are:

     

      -4 ± √18, or -4 ± 3√2

and thus the factors are x + 4 - 3√2 and x + 4 + 3√2

x = ---------------------

3 0
4 years ago
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