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3 years ago

Write a balanced chemical equation showing how each metal oxide reacts with HCl. SrO Na2O Li2O BaO

Chemistry

2 answers:

Agata [3.3K]3 years ago

6 0

Answer:

See below

Explanation:

Each metal oxide reacts with HCl to form water and the metal chloride

$\rm SrO + 2HCl \longrightarrow SrCl_{2} + H_{2}O\\\\Na_{2}O + 2HCl \longrightarrow 2NaCl + H_{2}O\\\\Li_{2}O + 2HCl \longrightarrow 2LiCl + H_{2}O\\\\BaO + 2HCl \longrightarrow BaCl_{2} + H_{2}O$

Annette [7]3 years ago

4 0

Answer:

Generally, metal oxides reacts with hydrochloric acid(HCl) to form the corresponding salts and water

SrO + 2HCl → SrCl2 + H2O

Na2O + 2HCl → 2NaCl + H2O

Li2O + 2HCl → 2LiCl + H2O

BaO + 2HCl → BaCl2 + H2O

Explanation:

Metal oxides are basic in nature .This means they have a high pH value ( >7 ). This is why if they react with acid the product becomes salt and water. Now let us write a balance equation between the following metal oxides and Hydrochloric acid(HCl) as stated in the questions.

SrO + 2HCl → SrCl2 + H2O

The above equation has the reactant at the left hand side and the products at the right hand side. Balancing the equation requires that the number of each element present on the reactant sides need to be equal on the product sides . Sr(strontium) has only one atom(SrO) and one atom of oxygen (SrO) on the reactant side. On the product side, Sr has one atom(SrCl) and one atom of oxygen(H2O). So Sr and O is balanced on both sides. The hydrogen on the product sides has 2 atom and the chlorine has 2 atom too . To balance the 2 atoms with that on the reactant side we add 2 in front of HCl to make hydrogen 2 atoms and chlorine 2 atoms.

Na2O + 2HCl → 2NaCl + H2O

Same method applied to balance the first equation is used here . Make sure every number of atom on the left side is equal to the right sides. The sodium is diatomic on the left and right sides. The oxygen has one atom on both sides .The hydrogen is diatomic on both sides and chlorine is diatomic on both sides. so the equation is balanced.

Li2O + 2HCl → 2LiCl + H2O

The equation is balance here as I added 2 in front of HCl to balance hydrogen and chlorine on both sides. And add 2 in front of LiCl to balance with the diatomic Chlorine and lithium on the reactant side.

BaO + 2HCl → BaCl2 + H2O

I only added 2 to the HCl acid to balance it with what we have on the right sides.

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Serggg [28]

Answer:

dissolving salt in water

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3 years ago

What is the change in temperature in a 128g sample of titanium if it absorbs 2808J of heat energy at a temperature of 2°C? The s

Katena32 [7]

Given:

128g sample of titanium

2808J of heat energy

specific heat of titanium is 0.523 J/ g °C.

Required:

Change in temperature

Solution:

This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.

Plugging in the values into the equation

H = mCpT

2808J = (128g) (0.523 J /g °C) T

T = 41.9 °C

3 0

3 years ago

Formula New Combination Predicted Formula

creativ13 [48]

Answer:

<span>Formula    New Combination Predicted Formula
</span>

NaCl            potassium + chlorine                KCl

AlCl₃             aluminum + fluorine                AlF₃

CO₂    tin + oxygen                              SnO₂

MgCl₂           calcium + bromine                   CaBr₂

HCl               cesium + iodine                       CsI

<span> CCl₄              silicon + bromine                     SiBr₄</span>

Explanation:

1) The question is incomplete. The first part is missing.

This is the first part of the question.

<span>Applying the principle that the elements of a particular column in the Periodic Table share the same chemical properties, complete the following chart. The first one has been done for you.
</span>

2) This is the given chart:

<span>Formula    New Combination Predicted Formula
</span>

Cu₂O           silver + oxygen                          Ag₂O   ← this is the example.

NaCl            potassium + chlorine

<span> AlCl₃             aluminum + fluorine </span>

CO₂    tin + oxygen

<span> MgCl₂           calcium + bromine </span>

<span> HCl               cesium + iodine </span>

<span> CCl₄              silicon + bromine </span>

3) This is how you find the new formula to complete the chart.

i) NaCl            potassium + chlorine

Since potassium is in the same group of sodium, you predict that in the new formula Na is replaced by K giving KCl.

ii) AlCl₃             aluminum + fluorine

Since fluorine is in the same group that Al, then you predict that in the new formula Cl is replaced by F leading to AlF₃

iii) CO₂    tin + oxygen

Since tin is in the same group that C, you predict that in the new formula C is replaced by Sn leading to SnO₂

iv) MgCl₂           calcium + bromine

Since calcium is in the same group that Mg, and bromine is in the same group that Cl, you predict thea in the new formula calcium replaces Mg and bromine replaces Cl, leading to CaBr₂

v) HCl               cesium + iodine

Since H is in the same column that cesium and Cl is in the same colum that iodine, you predict that in the new formula Cs replaces H and I replaces Cl leading to: CsI

<span> vi) CCl₄              silicon + bromine
</span>

Since silicon is in the same column that C and bromine is in the same column that Cl, you predict that in the new formula Si replaces C and Br replaces Cl, leading to SiBr₄

5 0

3 years ago

OFFERING 50 POINTS

defon

a. cesium and sulfur would be an ionic bond (metal + non-metal)

b. chlorine and bromine would be a covalent bond (non-metal+ non-metal)

c. magnesium and fluorine would be ionic again (metal + non-metal)

d. silver and mercury would be a metallic bond I'm pretty sure at least (metal+metal)

7 0

3 years ago

To what volume (in mL) would you need to dilute 25.0mL of a 1.45 m solution of Kcl to make a 0.0245m solution of KCl

dezoksy [38]

Answer:

The answer is

Explanation:

In order to calculate the volume needed we use the formula

$V_2 = \frac{C_1V_1}{C_2}$

where

C1 is the concentration of the stock solution

V1 is the volume of the stock solution

C2 is the concentration of the diluted solution

V2 is the volume of thevdiluted solution

From the question

C1 = 1.45 M

V1 = 25 mL

C2 = 0.0245 M

So we have

$V_2 = \frac{1.45 \times 25}{0.0245} = \frac{36.25}{0.0245} \\ = 1479.59...$

We have the final answer as

Hope this helps you

4 0

3 years ago