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3 years ago

Write a balanced chemical equation showing how each metal oxide reacts with HCl. SrO Na2O Li2O BaO

Chemistry

2 answers:

Agata [3.3K]3 years ago

6 0

Answer:

See below

Explanation:

Each metal oxide reacts with HCl to form water and the metal chloride

$\rm SrO + 2HCl \longrightarrow SrCl_{2} + H_{2}O\\\\Na_{2}O + 2HCl \longrightarrow 2NaCl + H_{2}O\\\\Li_{2}O + 2HCl \longrightarrow 2LiCl + H_{2}O\\\\BaO + 2HCl \longrightarrow BaCl_{2} + H_{2}O$

Annette [7]3 years ago

4 0

Answer:

Generally, metal oxides reacts with hydrochloric acid(HCl) to form the corresponding salts and water

SrO + 2HCl → SrCl2 + H2O

Na2O + 2HCl → 2NaCl + H2O

Li2O + 2HCl → 2LiCl + H2O

BaO + 2HCl → BaCl2 + H2O

Explanation:

Metal oxides are basic in nature .This means they have a high pH value ( >7 ). This is why if they react with acid the product becomes salt and water. Now let us write a balance equation between the following metal oxides and Hydrochloric acid(HCl) as stated in the questions.

SrO + 2HCl → SrCl2 + H2O

The above equation has the reactant at the left hand side and the products at the right hand side. Balancing the equation requires that the number of each element present on the reactant sides need to be equal on the product sides . Sr(strontium) has only one atom(SrO) and one atom of oxygen (SrO) on the reactant side. On the product side, Sr has one atom(SrCl) and one atom of oxygen(H2O). So Sr and O is balanced on both sides. The hydrogen on the product sides has 2 atom and the chlorine has 2 atom too . To balance the 2 atoms with that on the reactant side we add 2 in front of HCl to make hydrogen 2 atoms and chlorine 2 atoms.

Na2O + 2HCl → 2NaCl + H2O

Same method applied to balance the first equation is used here . Make sure every number of atom on the left side is equal to the right sides. The sodium is diatomic on the left and right sides. The oxygen has one atom on both sides .The hydrogen is diatomic on both sides and chlorine is diatomic on both sides. so the equation is balanced.

Li2O + 2HCl → 2LiCl + H2O

The equation is balance here as I added 2 in front of HCl to balance hydrogen and chlorine on both sides. And add 2 in front of LiCl to balance with the diatomic Chlorine and lithium on the reactant side.

BaO + 2HCl → BaCl2 + H2O

I only added 2 to the HCl acid to balance it with what we have on the right sides.

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Phosphorus pentachloride reacts with water to form hydrochloric acid and phosphoric acid. How many total moles of acid are forme

klio [65]

Answer:

0,13 moles of acid are produced

Explanation:

The reaction of the problem is:

PCl₅ + 4H₂O → 5HCl + H₃PO₄

Based on the reaction, 1 mole of PCl₅ produces 6 moles of acid (5 moles of HCl + 1 mole of H₃PO₄).

The molecular mass of PCl₅ is:

1P = 30,97g/mol + 5Cl = 5×35,45g/mol = <em>208,24 g/mol</em>

That means 4,5g of PCl₅ are:

4,5g PCl₅×(1mol / 208,24g) = 0,0216 moles of PCl₅. As 1 mole of PCl₅ produces 6 moles of acid, 0,0216 moles of PCl₅ produce:

0,0216 moles PCl₅ × (6 moles acid / mole of PCl₅) =

<em>0,13 moles of acid are produced</em>

I hope it helps!

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3 years ago

Consider an electron with charge âˆ’eâˆ’e and mass mmm orbiting in a circle around a hydrogen nucleus (a single proton) with cha

PtichkaEL [24]

Answer:

Explanation:

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$v^2=\frac{e^2}{4\pi \epsilon m r}$

$v=(\frac{e^2}{4\pi \epsilon m r})^{\frac{1}{2} }$

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