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3 years ago

Write a balanced chemical equation showing how each metal oxide reacts with HCl. SrO Na2O Li2O BaO

Chemistry

2 answers:

Agata [3.3K]3 years ago

6 0

Answer:

See below

Explanation:

Each metal oxide reacts with HCl to form water and the metal chloride

$\rm SrO + 2HCl \longrightarrow SrCl_{2} + H_{2}O\\\\Na_{2}O + 2HCl \longrightarrow 2NaCl + H_{2}O\\\\Li_{2}O + 2HCl \longrightarrow 2LiCl + H_{2}O\\\\BaO + 2HCl \longrightarrow BaCl_{2} + H_{2}O$

Annette [7]3 years ago

4 0

Answer:

Generally, metal oxides reacts with hydrochloric acid(HCl) to form the corresponding salts and water

SrO + 2HCl → SrCl2 + H2O

Na2O + 2HCl → 2NaCl + H2O

Li2O + 2HCl → 2LiCl + H2O

BaO + 2HCl → BaCl2 + H2O

Explanation:

Metal oxides are basic in nature .This means they have a high pH value ( >7 ). This is why if they react with acid the product becomes salt and water. Now let us write a balance equation between the following metal oxides and Hydrochloric acid(HCl) as stated in the questions.

SrO + 2HCl → SrCl2 + H2O

The above equation has the reactant at the left hand side and the products at the right hand side. Balancing the equation requires that the number of each element present on the reactant sides need to be equal on the product sides . Sr(strontium) has only one atom(SrO) and one atom of oxygen (SrO) on the reactant side. On the product side, Sr has one atom(SrCl) and one atom of oxygen(H2O). So Sr and O is balanced on both sides. The hydrogen on the product sides has 2 atom and the chlorine has 2 atom too . To balance the 2 atoms with that on the reactant side we add 2 in front of HCl to make hydrogen 2 atoms and chlorine 2 atoms.

Na2O + 2HCl → 2NaCl + H2O

Same method applied to balance the first equation is used here . Make sure every number of atom on the left side is equal to the right sides. The sodium is diatomic on the left and right sides. The oxygen has one atom on both sides .The hydrogen is diatomic on both sides and chlorine is diatomic on both sides. so the equation is balanced.

Li2O + 2HCl → 2LiCl + H2O

The equation is balance here as I added 2 in front of HCl to balance hydrogen and chlorine on both sides. And add 2 in front of LiCl to balance with the diatomic Chlorine and lithium on the reactant side.

BaO + 2HCl → BaCl2 + H2O

I only added 2 to the HCl acid to balance it with what we have on the right sides.

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madreJ [45]

Answer:

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Explanation: Try rewording the questions when looking it up. Hope this helps

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3 years ago

Read 2 more answers

A gas mixture contains 0.150 mol of oxygen (O2) gas and 0.211 mol of argon (Ar) gas. The total pressure of the mixture is 159 kP

Firdavs [7]

<h3><u>Answer;</u></h3>

Partial pressure of Ar = 92.934 kPa

<h3><u>Explanation;</u></h3>

Partial pressure of a gas = Mole fraction × Total pressure

Mole fraction = Number of moles of a gas /Total moles of gas

Therefore;

Mole fraction of Ar = 0.211 mol/ (0.211 + 0.150)

= 0.5845

Total pressure = 159 kPa

Hence;

Partial pressure of Ar = 0.5845 × 159 kPa

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4 years ago

The part of the flower responsible for producing pollen (sperm) is the _______.

IgorC [24]

Hello,

Here is your answer:

The proper answer to this question is option C "stigma".

Here is how:

The stigma is responsible for producing pollen in a plant.

Your answer is C.

If you need anymore help feel free to ask me!

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3 years ago

What is the pH of a solution within a solution with pH = 4.50? [H +] = 3.25×10-6 M?

Lisa [10]

Answer: 5.48

Explanation:

pH is the negative logarithm of hydrogen ion concentration in a solution.

Mathematically, pH = - log(H+)

where H+ represent the concentration of hydrogen ion

So, to get the pH of the solution with [H +] = 3.25×10-6 M:

Apply, pH = -log(H+)

pH = - log (3.25×10-6 M)

pH = - ( -5.48)

(Note that the minus signs will cancel out each other)

Therefore pH = 5.48

Now we know that the pH of the solution with hydrogen ion concentration of 3.25×10-6 M is 5.48 (i.e slightly acidic)

Thus, we can finally say 5.48 is the pH of the solution within a solution with pH = 4.50

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4 years ago

Avoiding an accident when driving can depend on reaction time. That time, measured in seconds from the moment the driver see dan

crimeas [40]

Answer:

The answer is below

Explanation:

A normal model is represented as (μ, σ). Therefore for (1.5, 0.18), the mean (μ) = 1.5 and the standard deviation (σ) = 0.18

The z score shows by how many standard deviations the raw score is above or below the mean. It is given as:

$z=\frac{x-\mu}{\sigma}$

a) For x < 1.35 s

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{1.35-1.5}{0.18}=-0.83$

From the normal distribution table, the percent of drivers have a reaction time less than 1.35 seconds = P(x < 1.35) = P(z < -0.83) = 0.2033 = 20.33%

b) For x > 1.9 s

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{1.9-1.5}{0.18}=2.22$

From the normal distribution table, the percent of drivers have a reaction time greater than 1.9 seconds = P(x > 1.9) = P(z > 2.22) = 1 - P(z<2.22) = 1 - 0.9868 = 0.0132 = 1.32%

c) For x = 1.45

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{1.45-1.5}{0.18}=-0.28$

For x = 1.75

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{1.75-1.5}{0.18}=1.39$

From the normal distribution table, P(1.45 < x < 1.75) = P(-0.28 < z < 1.39) = P(z < 1.39) - P(z< - 0.28) = 0.9177 - 0.3897 = 0.528 = 52.8%

d) A percentage of 10% corresponds to a z score of -1.28

$z=\frac{x-\mu}{\sigma}\\\\-1.28=\frac{x-1.5}{0.18}\\\\x-1.5=-0.2034\\\\x=1.27$

e) P(z < z1) - P(z< -z1) = 60%

P(z < z1) - P(z< -z1) = 0.6

P(z < -z1) = 1 - P(z < z1)

P(z<z1) - (1 - P(z < z1)) = 0.6

2P(z<z1) - 1= 0.6

2P(z<z1) = 1.6

P(z<z1) = 0.8

From the z table, z1 = 0.85

$0.85=\frac{x-1.5}{0.18}and-0.85=\frac{x -1.5}{0.18} \\\\x=1.65 \ and\ x=1.35$

The reaction time between 1.35 and 1.65 seconds

8 0

3 years ago