2 years ago

If t(d) = 3d + 1 and d(n) = 4n + 2, what is t(d(n)) when n = 5

Mathematics

1 answer:

Mkey [24]2 years ago

8 0

Answer:

Step-by-step explanation:

d(n) = 4n + 2

= 4(5) + 2

=22

t(d(n)) = 3(22) + 1

= 67

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If t(d) = 3d + 1 and d(n) = 4n + 2, what is t(d(n)) when n = 5​

If t(d) = 3d + 1 and d(n) = 4n + 2, what is t(d(n)) when n = 5