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3 years ago

Being fun again who whants points here is a question you'll get 50 points

Mathematics

2 answers:

stich3 [128]3 years ago

8 0

Answer:

0.46

Step-by-step explanation:bark brainliest plz

Colt1911 [192]3 years ago

6 0

0.46 pounds I think I may be wrong

You might be interested in

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

First of all, I just would like to say:

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Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! （＊＾Ｕ＾）人（≧Ｖ≦＊）/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

3 years ago

Which of the following numbers is a rational but not a integer

Temka [501]

Rational numbers are numbers that can be turned into a fraction. They can be negative or positive.
Integers are whole numbers. They can be negative or positive.

Numbers such as 0.10 are rational because they can be turned into a fraction
0.10 = 1/10....and since it is not a whole number, it is not an integer.

8 0

3 years ago

Solve for x^2 +11 + 121/4 = 125/4 for x

Ratling [72]

I hope this helps you

x^2 =125/4-121/4-11

x^2=4/4-11

x^2=1-11

x^2= -10

x= i.square root of 10

5 0

3 years ago

Write the equation of the line in slope-intercept form that has: slope: -1 and point: (1, 1)

lara31 [8.8K]

Answer:

f(x) = -1x + 1

Step-by-step explanation:

f(x) = mx + b

the equation above is slope intercept form. in order to make it you need a slope and a y intercept. you were given the slope, so now you need a y intercept. but where would you find that??? look no farther than the point you were given, (1,1). the y intercept is the second number in the parentheses. next you take your slope and your y-intercept and place them in.

f(x) = -1x + 1

hope i could help

3 0

3 years ago

Susan keeps track of the high and low temperatures every day for a week. The following table shows her data what is the average

uysha [10]

Answer:

10.75

Step-by-step explanation:

To get the average, we always SUM UP all the numbers and divide by the number of numbers.

We do this for "change" row since we want average of "change".

Let's add up all the changes:

11 + 12 + 10 + 10 + 11 + 10 + 11 = 75

How many numbers are there?

There are 7 numbers

Now, the average:

Average = Sum/Number of Numbers

Average = $\frac{75}{7}=10.75$

The average = 10.75

4 0

3 years ago