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Alex17521 [72]
3 years ago
14

Being fun again who whants points here is a question you'll get 50 points

Mathematics
2 answers:
stich3 [128]3 years ago
8 0

Answer:

0.46

Step-by-step explanation:bark brainliest plz

Colt1911 [192]3 years ago
6 0
0.46 pounds I think I may be wrong
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Madeline received $300 for her birthday. She deposits it into a savings account with an interest rate of 2.45%. She makes monthl
oee [108]

Answer:

  b.  $1,587.57

Step-by-step explanation:

A financial calculator will tell you the value of Madeline's account after  8 years will be $16,287.57. In that time, she will have deposited ...

  $300 +96×150 = $14,700

The interest earned is the difference between her account balance and the amount she deposited:

  $16,287.57 -14,700 = $1,587.57 . . . interest earned

_____

<em>Account value calculation</em>

The future value of the initial $300 deposit after 8 years is ...

  A = P(1 +r/n)^(nt)

for principal P earning annual rate r compounded n times per year for t years.

  A = $300(1 +0.0245/12)^(12·8) ≈ $364.89

The future value of the sum of $150 deposits monthly (at the beginning of the month) will be ...

  A = $150((1+r/n)^(nt) -1)(1 +n/r) = $15,922.68

So, the total value of Madeline's account in 8 years is ...

  $364.89 +15,922.68 = $16,287.57

_____

<em>Comment on account value</em>

In problems of this nature, it is always necessary to determine when the deposits are made relative to when the account value is measured. Here, we assume the $300 deposit is immediate, and its value is measured 8 years hence.

The monthly deposits are not described in that detail. In order to get any of the numbers in the answer list, we need to assume the deposits are at the beginning of the month. If we assume they are at the end of the month, the amount of interest is reduced by about $33.18, the last month's interest.

7 0
3 years ago
Elijah is selling coupon books for a school fundraiser. the coupon books sell for $11. the school gets $8 and $3 goes to elijah'
Sladkaya [172]
He collected $264.00, $72.00 went to his homeroom, and $192.00 to the school
6 0
3 years ago
Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam
tigry1 [53]

Answer:

P(A) = \frac{30}{100}

P(B) = \frac{77}{100}

P(A\ n\ B) = \frac{22}{100}

P(A\ u\ B) = \frac{85}{100}

Step-by-step explanation:

Given

See attachment for proper format of table

n = 100 --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

Yes = 22 and No = 8

So, we have:

n(A) = Yes + No

n(A) = 22 + 8

n(A) = 30

P(A) is then calculated as:

P(A) = \frac{n(A)}{Sample}

P(A) = \frac{30}{100}

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

(1) = 22    (2) = 25 and (3) = 30

So, we have:

n(B) = (1) + (2) + (3)

n(B) = 22 + 25 + 30

n(B) = 77

P(B) is then calculated as:

P(B) = \frac{n(B)}{Sample}

P(B) = \frac{77}{100}

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

n(A\ n\ B) = 22

The probability is then calculated as:

P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}

P(A\ n\ B) = \frac{22}{100}

Solving (d): P(A u B)

This is calculated as:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)

This gives:

P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}

Take LCM

P(A\ u\ B) = \frac{30+77-22}{100}

P(A\ u\ B) = \frac{85}{100}

8 0
3 years ago
A pole that is 2.5 m tall casts a shadow that is 1.07 m long. At the same time, a nearby tower casts a shadow that is
valkas [14]

Answer:

The tower is 61.65 meters tall.

Step-by-step explanation:

7 0
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