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katrin [286]
3 years ago
13

Evaluate for the given values of the variables.

Mathematics
1 answer:
Troyanec [42]3 years ago
7 0

Answer:

17) 26

18) 66

19) 78

20) 145

Step-by-step explanation:

#17) 8 + 3n for n = 6

8 + 3*(6)

8 + 18 = 26

#18) (8 + 3)n for n = 6

(8 + 3)*6

(11)*6 = 66

#19) 90 - 4d for d = 3

90 - 4*(3)

90 - 12 = 78

#20) 7x + 2y for x = 15, y = 20

7*(15) + 2*(20) = 145

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Whats 25% of 90 in full explanation
julia-pushkina [17]

Answer:

22.5

Step-by-step explanation:

The answer is 22.5 because you convert 25% to a decimal which equals .25. To make the percent a decimal, you move it two times to the left.

Then multiply

90 • .25 = 22.5

4 0
3 years ago
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1. A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts o
Sauron [17]

Answer:

The confidence interval estimate of the population mean is :

(0.61 ppm, 0.90 ppm)

The correct option is (A).

Step-by-step explanation:

The amounts of mercury​ (ppm) found in tuna sushi sampled at different stores in a major city are:

S = {0.58, 0.82, 0.10, 0.98, 1.27, 0.56, 0.96}

A (100-\alpha )\% confidence interval for the population mean (μ) is an interval estimate of the true value of the mean. This interval has a (100-\alpha )\% probability of consisting the true value of mean.

⇒ Since the population standard deviation is not provided we will use the <em>t</em>-distribution to construct the 99% confidence interval for mean.

⇒ The formula for confidence interval for the population mean is:

                                          \bar x\pm t_{\alpha/2,(n-1)}\times \frac{s}{\sqrt{n}}

Here,

\bar x = sample mean

<em>s </em>= sample standard deviation

<em>n</em> = sample size

t_{\alpha/2,(n-1)} = critical value.

The degrees of freedom for the critical value is, (<em>n</em> - 1) = 7 - 1 = 6.

The significance level is: \alpha =1-Confidence\ level=1-0.99=0.01

The critical value is:

t_{\alpha/2,(n-1)}=t_{0.01/2, 7}=t_{0.05,7}=3.143

**Use the <em>t</em>-table for the critical value.

Compute the sample mean and sample standard deviation as follows:

\bar x=\frac{1}{7}(0.58+ 0.82+ 0.10+ 0.98+ 1.27+ 0.56+ 0.96) =0.753

\int\limits^a_b {x} \, dx s=\sqrt{\frac{\sum (x{i}-\bar x)^{2}}{n-1} } =\sqrt{\frac{1}{6} \times 0.859743} =0.379

The 99% confidence interval for μ is:

x^{2} CI=0.753\pm 3.143\times\frac{0.379}{\sqrt{7}} \\=0.753\pm0.143\\=(0.61, 0.896)\\\approx(0.61, 0.90)

The confidence interval estimate of the population mean is:

(0.61 ppm, 0.90 ppm)

The upper and lower limit of the 99% confidence interval indicates that the true mean value is less than 1 ppm. This implies that there is not too much mercury in tuna sushi

Because it is possible that the mean is not greater than 1 ppm. Also, at least one of the sample values is less than 1 ppm, so at least some of the fish are safe.

Thus, the correct option is (A).

6 0
3 years ago
I need help asap<br><br> what is the mode of 63, 70, 75, 80, 85, 85, 85, 92, 92, 95, 99
Ann [662]
The mode would be 85 since it occurs the most out of the whole data set.
4 0
3 years ago
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Jace purchases a new motorcycle for $8000. The bike depreciates 12% every year.
Alex777 [14]

Answer:

We know that the original price of the bike was $8,000.

After one year, the price of the bike decays a 12%, then the new price of the bike is:

P(1) = $8,000*( 1 - 12%/100%) = $8,000*(1 - 0.12)

After another year, the price again decays a 12%, the new price will be:

P(2) = $8,000*(1 - 0.12)*(1 - 12%/100%) = $8,000*(1 - 0.12)*(1 - 0.12) = $8,000*(1 - 0.12)^2

We already can see the pattern here, after t years, the price of the bike will be:

P(t) = $8,000*(1 - 0.12)^t

With this equation, we can find the price of the bike after 5 years, where we only need to replace t by 5

We will get:

P(5) = $8,000*(1 - 0.12)^5 = $4,221.9

The price of the bike after 5 years is  $4,221.9.

Now we want two equations to represent this, so we need another.

This is kinda trivial, because there is only one equation that represents this, so we only can rewrite our equation in another form.

We could say that the price of the bike after t years is:

P(t) = $8,000*(0.88)^t

or something like:

P(t) = $7040*(0.88)^(t - 1)

Where i multiplied the initial value by 0.88, and then reduced the exponent by one.

3 0
2 years ago
Find the quotient.<br> 1.38÷0.3=
AleksandrR [38]

Answer: 4.6 is the answer to 1.38 divided by 0.3=4.6

6 0
2 years ago
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