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3 years ago

Which organisms develop gills from pharyngeal arches and later develop lungs to breathe on land

Physics

2 answers:

mihalych1998 [28]3 years ago

4 0

Answer:

These are the ones you can pick from. I'm on the question and I think it's frog and lizard?

Explanation:

lawyer [7]3 years ago

3 0

Apart from cutaneous respiration present in all species, most lissamphibians are born in an aquatic larval stage with gills. After metamorphosis, they develop lungs to breathe on land. The larvae of urodeles and apods present external, filamentous and highly branched gills which allow them to breathe underwater.

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While visiting the beach, you enjoy the warm ocean water, but the sand burns your feet. That night you walk along the beach and

garik1379 [7]

The answer would be B..

Since sand can heat up quickly, it will also cool off quickly. But water takes a long time to heat up and cool down.

8 0

3 years ago

A. What did the neuron say to the muscle say? (Use your basic physiological knowledge, such as the function of

Romashka-Z-Leto [24]

Answer:

Somatic motor neurons originate in the central nervous system, project their axons to skeletal muscles (such as the muscles of the limbs, abdominal, and intercostal muscles), which are involved in locomotion.

Explanation:

Muscles move on commands from the brain. Single nerve cells in the spinal cord, called motor neurons, are the only way the brain connects to muscles. When a motor neuron inside the spinal cord fires, an impulse goes out from it to the muscles on a long, very thin extension of that single cell called an axon.

4 0

2 years ago

In which direction does a convergent boundary move?

VladimirAG [237]

Answer:

Toward each other teehee merry christmas

Explanation:

7 0

2 years ago

Read 2 more answers

PLzzz helpppp

ioda

Answer: Charging.

Explanation: ...

5 0

1 year ago

Read 2 more answers

A force of 44 N will stretch a rubber band 88 cm (0.080.08 m). Assuming that Hooke's law applies, how far will aa 11-N forc

Setler79 [48]

Answer:

The rubber band will be stretched 0.02 m.

The work done in stretching is 0.11 J.

Explanation:

Force 1 = 44 N

extension of rubber band = 0.080 m

Force 2 = 11 N

extension = ?

According to Hooke's Law, force applied is proportional to the extension provided elastic limit is not extended.

F = ke

where k = constant of elasticity

e = extension of the material

F = force applied.

For the first case,

44 = 0.080K

K = 44/0.080 = 550 N/m

For the second situation involving the same rubber band

Force = 11 N

e = 550 N/m

11 = 550e

extension e = 11/550 = 0.02 m

The work done to stretch the rubber band this far is equal to the potential energy stored within the rubber due to the stretch. This is in line with energy conservation.

potential energy stored = $\frac{1}{2}ke^{2}$

==> $\frac{1}{2}* 550* 0.02^{2}$ = 0.11 J

3 0

2 years ago