If one resistor<span> is connected to a battery and has a </span>resistance<span> of 2 </span>ohms<span> and the battery has a </span>voltage<span> of 12 volts, the </span>current<span> passing through the </span>circuit<span> is </span>6 amps. If V=IxR, then I (current) = V (voltage)/ R (resistance<span>) = 12 V/2 </span>Ohms<span> = 6 amps.</span>
The current flowing in the circuit can be found by applying Ohm's law: where V is the voltage of the battery I is the current flowing in the circuit R is the resistance of the circuit
In our problem, V=12 V and , so if we re-arrange the previous equation and we use these data, we find the current in the circuit:
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