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olga nikolaevna [1]
3 years ago
11

Find the current passing through a circuit consisting of a battery and one resistor. The resistor has a resistance of 2 ohms and

the battery has a voltage of 12 volts.
A) 0.167 amps
B) 2 amps
C) 6 amps
D) 8 amps
Physics
2 answers:
-BARSIC- [3]3 years ago
4 0
If one resistor<span> is connected to a battery and has a </span>resistance<span> of 2 </span>ohms<span> and the battery has a </span>voltage<span> of 12 volts, the </span>current<span> passing through the </span>circuit<span> is </span>6 amps. If V=IxR, then I (current) = V (voltage)/ R (resistance<span>) = 12 V/2 </span>Ohms<span> = 6 amps.</span>
I am Lyosha [343]3 years ago
3 0
The current flowing in the circuit can be found by applying Ohm's law:
V=IR
where
V is the voltage of the battery
I is the current flowing in the circuit
R is the resistance of the circuit

In our problem, V=12 V and R=2 \Omega, so if we re-arrange the previous equation and we use these data, we find the current in the circuit:
I= \frac{V}{R}= \frac{12 V}{2 \Omega}=6 A

Therefore the correct answer is C).
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Given:

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So the spring is compressed 0.314 m from it's natural length.  However, we're asked to find the additional deformation from the original 50mm.

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