To increase the acceleration due to gravity, we will place the new station in a shorter radius which is 1.2 RE.
<h3>What is acceleration due to gravity?</h3>
- This is free fall of an object under the influence of gravitational pull.
The acceleration due to gravity of the new station due to Earth's gravity is calculated as follows;
where;
- g is the acceleration due to gravity
- G is gravitational constant
- M is the mass of the earth
- R is the radius of the earth
To increase the acceleration due to gravity, the radius of the earth must be decreased. Thus, we will place the new station in a shorter radius which is 1.2 RE.
Learn more about acceleration due to gravity here: brainly.com/question/88039
Answer:
adjust chosen Karl Karl jam halted Bernie
Answer: a convex lens forms a larger virtual image
Explanation: i just took the quiz
Answer:
He should stand from the center of laser pointed on the wall at 1.3 m.
Explanation:
Given that,
Wave length = 650 nm
Distance =10 m
Double slit separation d = 5 μm
We need to find the position of fringe
Using formula of distance
Put the value into the formula
Hence, He should stand from the center of laser pointed on the wall at 1.3 m.
Answer:
The question is incomplete, below is the complete question "A particle moves through an xyz coordinate system while a force acts on it. When the particle has the position vector r with arrow = (2.00 m)i hat − (3.00 m)j + (2.00 m)k, the force is F with arrow = Fxi hat + (7.00 N)j − (5.00 N)k and the corresponding torque about the origin is vector tau = (4 N · m)i hat + (10 N · m)j + (11N · m)k.
Determine Fx."
Explanation:
We asked to determine the "x" component of the applied force. To do this, we need to write out the expression for the torque in the in vector representation.
torque=cross product of force and position . mathematically this can be express as
Where
and the position vector
using the determinant method to expand the cross product in order to determine the torque we have
![\left[\begin{array}{ccc}i&j&k\\2&-3&2\\ F_{x} &7&-5\end{array}\right]\\\\](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C2%26-3%262%5C%5C%20F_%7Bx%7D%20%267%26-5%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C)
by expanding we arrive at
since we have determine the vector value of the toque, we now compare with the torque value given in the question
if we directly compare the j coordinate we have
