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olga nikolaevna [1]
3 years ago
11

Find the current passing through a circuit consisting of a battery and one resistor. The resistor has a resistance of 2 ohms and

the battery has a voltage of 12 volts.
A) 0.167 amps
B) 2 amps
C) 6 amps
D) 8 amps
Physics
2 answers:
-BARSIC- [3]3 years ago
4 0
If one resistor<span> is connected to a battery and has a </span>resistance<span> of 2 </span>ohms<span> and the battery has a </span>voltage<span> of 12 volts, the </span>current<span> passing through the </span>circuit<span> is </span>6 amps. If V=IxR, then I (current) = V (voltage)/ R (resistance<span>) = 12 V/2 </span>Ohms<span> = 6 amps.</span>
I am Lyosha [343]3 years ago
3 0
The current flowing in the circuit can be found by applying Ohm's law:
V=IR
where
V is the voltage of the battery
I is the current flowing in the circuit
R is the resistance of the circuit

In our problem, V=12 V and R=2 \Omega, so if we re-arrange the previous equation and we use these data, we find the current in the circuit:
I= \frac{V}{R}= \frac{12 V}{2 \Omega}=6 A

Therefore the correct answer is C).
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what is the dot product and cross product of of two vectors if the angle is between them is 90 degree?​
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\sf{\pink{\underline{\underline{\blue{GIVEN:-}}}}}

  • The angle between the two vectors is 90° .

\sf{\pink{\underline{\underline{\blue{TO\: FIND:-}}}}}

  1. The dot product of two vectors .
  2. The cross product of two vectors .

\sf{\pink{\underline{\underline{\blue{SOLUTION:-}}}}}

⚡ Let \rm{\vec{a}} and \rm{\vec{b}} are the two vectors .

✍️ We have know that,

\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:.\:\vec{b}\:=\:ab\cos{\theta}\:}}}}

Where,

  • θ = 90°

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\cos{90^{\degree}}\:}

  • cos 90° = <u>0</u>

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:ab\times{0}\:}

\rm{\implies\:\vec{a}\:.\:\vec{b}\:=\:0\:}

\rm{\red{\therefore}} [1] The dot product of two vectors is “ <u>0</u> ” .

✍️ We have know that,

\orange\bigstar\:\rm{\pink{\boxed{\green{\vec{a}\:\times\:\vec{b}\:=\:ab\sin{\theta}\:}}}}

Where,

  • θ = 90°

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\sin{90^{\degree}}\:}

  • sin 90° = <u>1</u>

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\times{1}\:}

\rm{\implies\:\vec{a}\:\times\:\vec{b}\:=\:ab\:}

\rm{\red{\therefore}} [2] The cross product of two vectors is “ <u>ab</u> ” .

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