Match the technology that uses radio waves to the field in which it is used.
1 answer:
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A) See ray diagram in attachment (-6.0 cm)
By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:
where
q is the distance of the image from the lens
f = -10 cm is the focal length (negative for a diverging lens)
p = 15 cm is the distance of the object from the lens
Solving for q,
B) The image is upright
As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:
where are the size of the image and of the object, respectively.
Since q < 0 and p > o, we have that , which means that the image is upright.
C) The image is virtual
As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.
This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual
Answer:
a) Both blocks displace the same amount of water.
Explanation:
Specific gravity (S.G.) is a quantity that tells how much and object is submerged on water and is given by:
with ρ the densities
Density of water is and density of aluminum is
So:
A S.G. value bigger than one means the object is totally submerged so the water displaced is equal to the volume of the cube.
For the lead (density = ) block we're going to calculate specific gravity in this case:
Again S.G gravity is bigger than 1, so the lead block is totally submerged too, that implies the volume of water displaced is the volume of the block, that is the same volume as the aluminum block, so a is the correct one.