Question

the temperature of a gas is raised from 10 to 20 degree celsius. Will the volume double the pressure if mass and pressure do not change? Why or why not? show calculations

Answer 1

Answer:

There will be No change in volume.  

Explanation:

Ideal Gas Equation is used to solve this :

PV=nRT;

P is pressure in Pa,

V is volume in $m^3$,

n is number of moles of gas;

R is the universal gas constant, 8.31 J/K mol

T is temperature in Kelvin

when mass is said to be fixed, the number of moles will also  be fixed, too. So  combining  both the constant term n and R which gives

PV=kT

where k is  constant.

V=   $\frac{k T}{P}$

So the equation represents that,  Volume V will remains unchanged  when  pressure and  temperature  are both doubled, therefore the numerator term T and the denominator term P are both  gets affected by multiplication of 2, hence by cancellations:

V =   $\mathrm{k} \frac{T \times 2}{P \times 2}$= $\frac{k T}{P}$