Question

What is the kb of the base po−34 given that a 0. 48m solution of the base has a ph of 12. 70? the equation described by the kb value is:___________

Answer 1

The equation described by the kb value is 5.21 x $10^-^3$.

The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.

Assuming  PO₄³⁻ (the phosphate anion).

PO₄³- + H₂O ==> HPO₄²⁻ + OH⁻

Kb = [HPO₄²⁻][OH⁻] / [PO₄³⁻]

We can find the [OH⁻] from the pH of 12.70.

pH + pOH = 14

14.0 - 12.7 = 1.3 = pOH

[OH] = 1x$10^-^1^.^3$

[OH-] = 5.0x$10^-^2$ M

[HPO₄²⁻] = 5.0x$10^-^2$ M

Kb = (5.0x$10^-^2$)2 / 0.48

     = 2.5x$10^-^3$ / 0.48

Kb = 5.21 x $10^-^3$

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