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Sonbull [250]
3 years ago
10

]Which of the following describes the arrangement of particles in plasma?The particles are ionized and move independently of eac

h other.,The particles are packed tightly together but vibrate rapidly against each other., The particles are locked together and are unable to move., The particles are held together, but they have the ability to flow past each other.
Chemistry
2 answers:
Ugo [173]3 years ago
4 0
The arrangement of the particles in a plasma would be that the particles are ionized and move independently of each other. Plasma is also called an ionized gas where it has free charged particles and are moving regardless of each other.
Romashka-Z-Leto [24]3 years ago
4 0

Answer: Option (a) is the correct answer.

Explanation:

Plasma is defined as the state of matter which is a hot ionized gas that contains positive particles and negative electrons.

Since plasma is a hot gas therefore, its particles move rapidly and independently from one place to another.

As a result, they have very high kinetic energy.

Hence, we can conclude that the statement particles are ionized and move independently of each other, best describes the arrangement of particles in plasma.

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Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e
notsponge [240]

<u>Answer:</u> The concentration of Sn^{2+} in the cell is 9.0\times 10^{-3}M

<u>Explanation:</u>

We are given:

<u>Oxidation half reaction:</u>  Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-   E^o_{Zn^{2+}/Zn}=-0.76V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)   E^o_{Sn^{2+}/Sn}=-0.136V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.136-(-0.76)=0.624V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}

where,

E_{cell} = electrode potential of the cell = 0.660 V

E^o_{cell} = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

[Zn^{2+}]=2.5\times 10^{-3}M

[Sn^{2+}] = ?

Putting values in above equation, we get:

0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})

[Sn^{2+}]=9.0\times 10^{-3}M

Hence, the concentration of Sn^{2+} ions is 9.0\times 10^{-3}M

3 0
3 years ago
3. The diet of white-tailed deer consists primarily of shrubs. Sika are
olga_2 [115]
Sika have more food choices because they eat both grasses and shrubs, compared to the white-tailed dear who only eats shrubs.
3 0
2 years ago
In a chemical equation, (aq) after one of the substances means that it is which of these? a solid formed from two ionic substanc
Vladimir79 [104]
The answer is dissolved in water, because in chemistry, (aq) is shorthand for aqueous solution.
3 0
3 years ago
What is the charge on an atom after it gains two electrons during the formation of a bond?
scoundrel [369]

Answer:

negative or neutral

Explanation:

electrons have a negative charge

  • the atom can be balanced by the negative charge if it was at two protons before

6 0
3 years ago
Read 2 more answers
Silicon carbide (SiC) is an important ceramic material made by reacting sand (silicon dioxide, SiO2) with powdered carbon at a h
makkiz [27]

Answer:

Percent yield of SiC is 77.0%.

Explanation:

Balanced reaction: SiO_{2}+3C\rightarrow SiC+2CO

Molar mass of SiC = 40.11 g/mol

Molar mass of SiO_{2} = 60.08 g/mol

So, 100.0 kg of SiO_{2} = \frac{100.0\times 10^{3}}{60.08} moles of SiO_{2} = 1664 moles of SiO_{2}

According to balanced equation, 1 mol of SiO_{2} produces 1 mol of SiC

Therefore, 1664 moles of SiO_{2} produce 1664 moles of SiC

Mass of 1664 moles of SiC = (1664\times 40.11)g = 66743g = 66.74 kg (4 sig. fig.)

Percent yield of SiC = [(actual yield of SiC)/(theoretical yield of SiC)]\times 100%

                                 = \frac{51.4kg}{66.74kg}\times 100 %

                                 = 77.0%

4 0
3 years ago
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