Answer: B, D, and maybe E. Check my explanation for 'E'
Step-by-step explanation:
There are a few ways of visualizing the expression, but Ill try to show it to easiest way possible.
![x^\frac{3}{2} =(x^3)^\frac{1}{2}](https://tex.z-dn.net/?f=x%5E%5Cfrac%7B3%7D%7B2%7D%20%3D%28x%5E3%29%5E%5Cfrac%7B1%7D%7B2%7D)
Notice nothing was changed because of the property of exponents. An exponent to a power means to multiply them. A thing you should remember for all future cases is that the one-half power means square root. It is the exact same thing. Therefore the new expression I created is the square root of 'x' cubed.
A:) This would be equivalent to x^2/3
B:) This is equivalent to x^3/2 because the square root is the 1/2 power to the power of 3.
C:) This would be equivalent to x^2/3
D:) This is equivalent to x^3/2 because the square root is the 1/2 power, but multiplied by the power under the radical.
E:) If this answer is to the third power, then it is equivalent. I cannot tell from this picture.
Answer:
Domain: All the real numbers
Range: All the real numbers
Step-by-step explanation:
The domain of a function is the complete set of possible values of the independent variable 'x'. That is to say, all the values that 'x' can take:
In this case, f(x)= 2x+1, the independent variable has no restrictions. Meaning that 'x' can take all the Real Values. In set notation: x∈ℝ.
The range of a function is the complete set of all possible resulting values of the dependent variable 'y'. In this case, given that the independent variable has no restrictions, the dependent variable 'y' can take any value. So, the range is: y ∈ ( −∞, ∞ ) - All the real numbers.
Answer:
what is poverty and what is seasonal poverty
Solution: The given problem is a binomial distribution.
The probability that a team member receives a scholarship is ![\frac{8}{12} = 0.67](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B12%7D%20%3D%200.67)
Therefore, the given problem follows binomial with n = 5 and p = 0.6667
Now the probability that 4 of 5 players selected are on scholarship is:
![P(x=4) = \binom{5}{4} \times 0.6667^{4} (1-0.6667)^{5-4}](https://tex.z-dn.net/?f=P%28x%3D4%29%20%3D%20%5Cbinom%7B5%7D%7B4%7D%20%5Ctimes%200.6667%5E%7B4%7D%20%281-0.6667%29%5E%7B5-4%7D)
![=5 \times 0.1976 \times 0.3333](https://tex.z-dn.net/?f=%3D5%20%5Ctimes%200.1976%20%5Ctimes%200.3333)
![=0.329](https://tex.z-dn.net/?f=%3D0.329)
Therefore, the probability that 4 of 5 players selected are on scholarship is 0.329
I don’t know sorry please somebody else can help you