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bazaltina [42]
3 years ago
9

Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges

zero? Express your answer in terms of some or all of the variables s, q1, q2 and k =14πϵ0. If your answer is difficult to enter, consider simplifying it, as it can be made relatively simple with some work.
Physics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})

Explanation:

Here two charges are placed at distance "d" apart

now the net value of electric field at some position between two charges will be ZERO

so we will have

electric field due to charge 1 = electric field due to charge 2

E_1 = E_2

Let the position where net field is zero will lie at distance "r" from q1

\frac{kq_1}{r^2} = \frac{kq_2}{(d-r)^2}

now we will have

\frac{(d - r)^2}{r^2} = \frac{q_2}{q_1}

now square root both sides

\frac{d}{r} - 1 = \sqrt{\frac{q_2}{q_1}}

now we have

\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1

so we have

r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})

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Viefleur [7K]

Answer: the sample of solid has less energy than the sample of gas

Explanation:

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5 0
3 years ago
What is the energy in joules of a mole of photons associated with visible light of wavelength 486 nm?
Marrrta [24]

Answer:

2.46\cdot 10^5 J

Explanation:

The enegy of a single photon is given by:

E=\frac{hc}{\lambda}

where

h is the Planck costant

c is the speed of light

\lambda is the wavelength of the photon

In this problem,

\lambda=486 nm=4.86\cdot 10^{-7}m

so the energy of one photon is

E_1=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.86\cdot 10^{-7}m}=4.09\cdot 10^{-19} J

1 mole of photons contains a number of Avogadro of photons:

N_A = 6.022\cdot 10^{23}

therefore, the total energy of 1 mole of these photons will be

E=N_A E_1 = (6.022\cdot 10^{23})(4.09\cdot 10^{-19} J)=2.46\cdot 10^5 J

3 0
4 years ago
A normal human heart, beating about once per second, creates a maximum 4.00 mV 4.00 mV potential across 0.250 m 0.250 m of a per
ElenaW [278]

Answer:

1) maximum electric field strength = 0.016 V/m

2)maximum magnetic field strength = 5.33 x 10^(-11) T

3) wavelength = 3 x 10^(8)m

Explanation:

A) We are given;

Frequency (f) = 1 Hz

Maximum Potential ΔV = 4 mV = 4 x 10^(-3) V

Length; d = 0.25 m

Now, maximum potential formula is given as;

ΔV = E_o•d

Where E_o is maximum electric field strength.

Thus,

E_o= ΔV/d = (4 x 10^(-3))/0.25 = 0.016 V/m

B) The maximum magnetic field strength is given by;

B_o = E_o/c

Where;

c is speed of light = 3 x 10^(8)

B_o is maximum magnetic field strength

Thus,

B_o = 0.016/(3 x 10^(8)) = 5.33 x 10^(-11) T

C) Speed of any electromagnetic wave is given by;

c = fλ

Where;

f is frequency

λ is wavelength

c is speed of light = 3 x 10^(8)

Thus, making λ the subject,

λ = c/f

λ = (3 x 10^(8))/1 = 3 x 10^(8)m

8 0
4 years ago
Water! Water! Water! The universal solvent. It is a compound made up of two elements: hydrogen and oxygen. How does water differ
ruslelena [56]

Explanation:

Water is compound made up of hydrogen and oxygen atoms.

Hydrogen and oxygen are elements that are joined together to form water.

A compound is a substance composed of two or more kinds of atoms/elements joined together in a definite grouping. The properties of a compound are different from those of the individual elements that are combined to make them up.

Water is made up of hydrogen and oxygen atoms in a ratio of 2 to 1;

An element is a distinct substance that cannot split up into simpler substances. Such substances are made up of one kind of atom. Hydrogen and oxygen are elements.

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4 0
3 years ago
Three forces in the x-y plane act on a 6.80 kg mass: 10.10 N directed at 19o, 8.60 N directed at 122o, and 9.80 N directed at 21
g100num [7]

Answer: a = 1.58 m/s²

Explanation: The mass of the object is 6.80kg.

From newton's second law of motion,

Resultant force = mass * acceleration

So we need to get the resultant force first.

Note all angles are measured from the positive x axis in the counter clockwise direction..

The first force is 10.10 N at an angle of 19° to the positive x axis.

Horizontal component of this force = 19× cos 19° =17.964 N

Vertical component of this force = 19 × sin 19° = 6.186N

The second force is 8.6 N, 122° ( 22° to the positive y axis), due to the angle, the force is between the positive y axis and negative x axis ( 2nd quadrant)

Horizontal component of this force = - 8.6×sin 22 = - 3.22 N

Vertical component of this force = 8.6 × cos 22 = 7.974 N

The third force is 9.8 N, 218° ( 38 degree to the negative axis), due to the angle, the force is placed in between the negative x and negative y axis.

Horizontal component of this force = - 9.8×cos 38 = - 7.722 N

Vertical component of this force = - 9.8 × sin 38 = - 6.033 N

Sum of forces on the x axis (fx) = 17.964 - 3.22 - 7.722 = 7.022 N

Sum of forces on the y axis (fy) = 6.186 + 7.974 - 6.033 = 8.127 N

Resultant force = √(fx) ²+(fy)²

Resultant force = √7.022² + 8.127²

Resultant force = √115.356613

Resultant force = 10.74 N

Recall that resultant force = mass * acceleration

10.74 = 6.8 × a

a = 10.74/6.8

a = 1.58 m/s²

8 0
4 years ago
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