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bazaltina [42]
3 years ago
9

Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges

zero? Express your answer in terms of some or all of the variables s, q1, q2 and k =14πϵ0. If your answer is difficult to enter, consider simplifying it, as it can be made relatively simple with some work.
Physics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})

Explanation:

Here two charges are placed at distance "d" apart

now the net value of electric field at some position between two charges will be ZERO

so we will have

electric field due to charge 1 = electric field due to charge 2

E_1 = E_2

Let the position where net field is zero will lie at distance "r" from q1

\frac{kq_1}{r^2} = \frac{kq_2}{(d-r)^2}

now we will have

\frac{(d - r)^2}{r^2} = \frac{q_2}{q_1}

now square root both sides

\frac{d}{r} - 1 = \sqrt{\frac{q_2}{q_1}}

now we have

\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1

so we have

r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})

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A model rocket is launched directly upward at a speed of 16 meters per second from a height of 2 meters. The function f(t)=−4.9t
Crank

Answer:

Hmax=15.06 meters

Explanation:The question ask for the maximum value of the function f(t) which can be find by find the maxima of the function

The maxima of the function occurs when the slope is zero. i.e.

\frac{df}{dt} =0\\\frac{df}{dt} =\frac{d}{dt} (-4.9t^2+16t+2)\\\frac{df}{dt} =-4.9*2t+16\\-9.8t+16=0\\t=16/9.8\\t=1.63 secs

Hence the maxima occurs at t=1.63 seconds

The maximum value of f is

f(1.63)=-4.9(1.63^2)+16(1.63)+2\\f(1.63)=15.06\\

hence maximum height is found to be

Hmax=15.06 meters

8 0
3 years ago
What additional information do you need to prove ∆ABC ≅ ∆DEF by the SAS Postulate?
miv72 [106K]

Answer:

Option A

You need a Angle C congruent to angle F

Explanation:

EX) Side angle Side = sas

6 0
3 years ago
How many days are in 345000 minutes? (Set up by dimensional analysis)​
Komok [63]
239.583 days is the answer
3 0
2 years ago
Paying off your debts will most likely
g100num [7]
I think the answer is d
4 0
2 years ago
If the fundamental frequency of a musical instrument is 42Hz, what is the frequency of the second harmonic?
timurjin [86]
For the majority of instruments f = n f0 where f is the resonating frequency, n is any whole number and f0 is the fundamental. 
<span>This applies to trumpets, violins, flutes and a broad range. </span>
<span>In such a </span>case<span> the first harmonic would be at n=1 and the second harmonic would be at n=2 </span>

<span>which gives a frequency of 84 Hz</span>
7 0
3 years ago
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