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Rudiy27
2 years ago
5

PLEASE help its timed..

Physics
1 answer:
mojhsa [17]2 years ago
3 0

Answer:

D

Explanation:

by increasing the distance through which force is applied, by changing the direction of force applied or by multiplying force of speed of the energy applied

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A box moves 1000 m horizontally as a force F 2000 N is applied downward. What is the work done on the box by F during the displa
stiks02 [169]

Answer:

D. OJ

Explanation:

5 0
3 years ago
An object is moving east with a constant speed of 30 m/s for 5 seconds. What is the object’s acceleration?
Shtirlitz [24]

Answer:

6 m/s²

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 30 m/s

Time (t) = 5 s

Acceleration (a) =..?

Acceleration is defined mathematically as:

Acceleration (a) = Velocity (v) /time (t)

a = v /t

With the above formula, we can obtain the acceleration of the object as follow:

Velocity (v) = 30 m/s

Time (t) = 5 s

Acceleration (a) =..?

a= v/t

a= 30/5

a = 6 m/s²

Therefore, the acceleration of the object is 6 m/s² due East.

7 0
3 years ago
What name is given to a process where a substance melts under pressure?​
Digiron [165]

Answer:

Melting

Explanation:

The process of a solid becoming a liquid is called melting. (an older term that you may see sometimes is fusion). The opposite process, a liquid becoming a solid, is called solidification. For any pure substance, the temperature at which melting occurs—known as the melting point—is a characteristic of that substance.

8 0
2 years ago
A box of books has _______inertia than a box of cotton balls.
White raven [17]

Talking about a quantity of inertia is exactly the same as talking about a quantity of mass.  So, if the boxes are anywhere near the same size, then the box of books has <u><em>more</em></u> inertia than the box of cotton balls, because books have more mass than an identical volume of cotton.

4 0
3 years ago
Read 2 more answers
What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per
Brilliant_brown [7]

Answer:

a_{cp}=7.77m/s^2

Explanation:

The equation for centripetal acceleration is a_{cp}=\frac{v^2}{r}.

We know the wheel turns at 45 rpm, which means 0.75 revolutions per second (dividing by 60), so our frequency is f=0.75Hz, which is the inverse of the period T.

Our velocity is the relation between the distance traveled and the time taken, so is the relation between the circumference C=2\pi r and the period T, then we have:

v=\frac{C}{T}=2\pi r f

Putting all together:

a_{cp}=\frac{(2\pi r f)^2}{r}=4 \pi^2f^2r=4 \pi^2(0.75Hz)^2(0.35m)=7.77m/s^2

4 0
3 years ago
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