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3 years ago

Please answer asappppp

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

5 0

Answer:

its D

Step-by-step explanation:

it is constent so its not C and it decreases so its not A

would you let me know what it is if you get it plz and if its wrong im sry

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An elevator starts at floor 5. It goes up 6 floors twice, and then it goes down 8 floors. A second elevator

omeli [17]

Answer:

Part 1 is ELevator 2 because elevator one ends on floor 9 and elevator 2 ends on floor 23. Part 2 is Elevator 1 ends on floor 9 and Elevator 2 ends on floor 23.

Step-by-step explanation:

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2 years ago

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I need help on this question

Over [174]

1 bushel = 186 heads of lettuces

multiply each side by 6

6 bushels = 1,116 heads of lettuces

The farmer picked 1,116 heads of lettuces

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3 years ago

Give the equation of the circle centered at the origin and passing through the point (0,5)

Julli [10]

Answer:

$x^{2} +y^{2}=25$

Step-by-step explanation

The standard equation of a circle centered at origin is $x^{2} +y^{2} =r^{2}$

r = radius of the circle

The circle is passing through the point (0,5)

∴ radius $r=\sqrt{(0-0)^{2}+(5-0)^{2} }$

$r=\sqrt{0+25}$

$r=\sqrt{25}$

$r^{2}=25$

∴ The equation of the circle is

$x^{2} +y^{2} = 25$

5 0

3 years ago

A candle in the shape of a circular cone has a base of radius r and a height of h that is the same length as the radius. which e

ladessa [460]

Answer:

$\frac{r(1-\sqrt{2})}{-3}$

Step-by-step explanation:

Volume of cone = $\frac{1}{3} \pi r^{2} h$

Since we are given that a circular cone has a base of radius r and a height of h that is the same length as the radius

= $\frac{1}{3} \pi r^{2} \times r$

= $\frac{1}{3} \pi r^{3}$

Surface area of cone including 1 base = $\pi r^{2} +\pi\times r \times \sqrt{r^2+h^2}$

Since r = h

So, area = $\pi r^{2} +\pi\times r \times \sqrt{r^2+r^2}$

= $\pi r^{2} +\pi\times r \times \sqrt{2r^2}$

= $\pi r^{2} +\pi\times r^2 \times \sqrt{2}$

Ratio of volume of cone to its surface area including base :

$\frac{\frac{1}{3} \pi r^{3}}{\pi r^{2} +\pi\times r^2 \times \sqrt{2}}$

$\frac{\frac{1}{3}r}{1+\sqrt{2}}$

$\frac{r}{3(1+\sqrt{2})}$

Rationalizing

$\frac{r}{3(1+\sqrt{2})} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}$

$\frac{r(1-\sqrt{2})}{-3}$

Hence the ratio the ratio of the volume of the candle to its surface area(including the base) is $\frac{r(1-\sqrt{2})}{-3}$

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3 years ago

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Lunna [17]

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3 years ago