Answer:
50n
Step-by-step explanation:
This problem can be solved using concept of Arithmetic progression(AP)
In AP series
the series increases or decreases by certain number which is called common difference.
common difference d is given by
d= nth term - (n-1)th term
nth term = a + (n-1)d
where a is the first term of the series
thus series can be a , a+d, a+2d, a+3d, a+4d, ...........a + (n-1)d
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Given series
50, 100, 150, 200
a = 50
to find d lets use 3rd term as nth term and 2nd term as (n-1)th term
d = 150 -100 = 50
Thus,
nth term = 50 + 50(n-1) = 50 + 50n -50 = 50n
50n can represent the position of the term of the sequence.
To validate this lets put n = 4
50*4 = 200 which is the same as the fourth term given in the series.
hence our solution is correct.
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