Answer:
B
Step-by-step explanation:
Supplementary angles sum to 180°, hence
3x + 9 + 2x + 2 = 180, that is
5x + 11 = 180 ( subtract 11 from both sides )
5x = 169 ( divide both sides by 5 )
x = 33.8
Hence the smaller angle has a measure of
2x + 2 = (2 × 33.8) + 2 = 67.6 + 2 = 69.6° → B
Answer:
Yes
Step-by-step explanation:
ΔMNL ≅ ΔQNL by ASA or AAS
by ASA
Proof:
∠ LNM = ∠LNQ =90
LN = LN {Common}
∠MLN = ∠QLN {LN bisects ∠ L}
By AAS
∠Q + ∠QLN + ∠LNQ = 180 {Angle sum property of triangle}
∠Q + 32 + 90 = 180
∠Q + 122 = 180
∠Q = 180 -122 =
∠Q = 58
∠Q = ∠M
∠MNL =∠QNL = 90
LN = LN {common side}
Answer:
<u>______________________________________________________</u>
<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>
For any right angled triangle with one angle α ,
or 
or 
<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>
- <u></u>
or 
- <u></u>
or 
<u>______________________________________________________</u>
Now , lets come to the question.
In a right angled triangle , let one angle be α (in place of theta) .
So , lets solve L.H.S.
= R.H.S.
∴ L.H.S. = R.H.S. (Proved)
Step-by-step explanation:
let's look at the full numbers under the square roots when bringing the external factors back in :
sqrt(9×9×2) - sqrt(3×3×7) + sqrt(8) - sqrt(28)
and let's present these numbers as the product of their basic prime factors
sqrt(3×3×3×3×2) - sqrt(3×3×7) + sqrt(2×2×2) - sqrt(2×2×7)
now we see that we have 2 pairs of square roots : 1 pair ends with a factor of 2, and one pair with a factor of 7.
let's combine these
sqrt (3×3×3×3×2) + sqrt(2×2×2) - sqrt(3×3×7) - sqrt (2×2×7)
and now we move the factors of 2 and 7 back out in front (of course, we need to apply the square root on these factors) :
9×sqrt(2) + 2×sqrt(2) - 3×sqrt(7) - 2×sqrt(7) =
= (9+2)×sqrt(2) - (3+2)×sqrt(7) = 11×sqrt(2) - 5×sqrt(7)
and that is the first answer option.
