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joja [24]
3 years ago
12

(a) 5.33 cm

Mathematics
1 answer:
PolarNik [594]3 years ago
3 0

Answer:

es la b 6.33 amigo ;) adios

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romanna [79]
Lol that’s poggers dude
7 0
3 years ago
Find an obtuse angle whose sine is<br> a) 0.25<br> b) 0.75<br> c) 0.875<br> d) 0.3465
swat32

Answer:

a) 165.52 degrees.

b)  131.41 degrees.

c)  118.96 degrees.

d)  159.73 degrees.

Step-by-step explanation:

The sine of an obtuse angle is positive as it is in the second quadrant.

a) Using a calculate the angle whose sine ( arcsin) is 0.25  = 14.478 degrees

so the obtuse angle  = 180 - 14.478 = 165.52 degrees to nearest hundredth

b) c) and d) are calculated in the same way.

7 0
3 years ago
Manager Roberts watched from the dugout as her baseball team took the field. It was the ninth inning and her players were locked
Roman55 [17]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Some of the data is missing in the question, which is defined in attached. please find it.

For point 1: P - 8- Roe  

For point 2:  C - 1- Schmoe

For point 3: 1B - 4 - Blow

For point 4: 2B - 2 - Kent

For point 5: SS - 9 - Kowalski

For point 6: 3B - 3 - Simmons

For point 7: LF - 5 - Schmidt

For point 8: CF - 6 - Kitt

For point 9: RF - 7 - Whitt

7 0
3 years ago
What is the average rate of change of the annual population between 1930 and 1950?
Rasek [7]

Answer:

the average rate of change is 5000

5 0
3 years ago
Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sampl
kompoz [17]

Complete Question

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sample of 15 students, the professors find the mean number of headaches is 19 and the standard deviation is 1.7. Assume the population distribution of number of headaches is normal.the correct conclusion at \alpha =0.001 is?

Answer:

There is no sufficient evidence to support the professor believe

Step-by-step explanation:

From the question we are told that

     The population mean is  \mu =  18

     The sample size is  n  =  15

      The sample mean is  \=  x  =  19

      The standard deviation is  \sigma =  1.7

      The level of significance is  \alpha  =  0.001

The null hypothesis is  H_o:  \mu = 18

The  alternative hypothesis is  H_a :  \mu > 18

 The critical value of the level of significance from the normal distribution table is    

         Z_{\alpha } =  3.290527

The test hypothesis is mathematically represented as

           t =  \frac{\= x  -  \mu }{ \frac{\sigma}{ \sqrt{n} } }

substituting values  

         t =  \frac{ 19  - 18}{ \frac{1.7}{ \sqrt{15} } }

         t =  2.28

Looking at the value of  t and  Z_{\alpha } we can see that t <  Z_{\alpha } so we fail to reject the null hypothesis.

This mean that there is no sufficient evidence to support the professor believe

     

       

3 0
4 years ago
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