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3 years ago

How are electrons represented in orbitals?

1 answer:

8 0

Electrons move in atomic orbitals (or subshells). there are four different orbital shapes (s p d f). in each shell, the s subshell is at a lower energy than the p. an orbital diagram is used to determine an atom's electron configurations

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How are progression and variation similar?

borishaifa [10]

Answer:

Explanation:

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3 years ago

Explain how the data collected and the calculations for the first and second resonance points in today's experiment would change

grandymaker [24]

Answer:

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Explanation:

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3 years ago

The driver of a car traveling at 31.3 m/s applies the brakes and undergoes a constant deceleration of 1.6 m/s2.How many revoluti

lisov135 [29]

Answer:

$R=156.99\operatorname{Re}vs$

Explanation: The equations used are as follows:

$\begin{gathered} x(t)=x_o+v_ot+\frac{1}{2}at^2\Rightarrow(1) \\ v(t)=v_o+at\Rightarrow(2) \end{gathered}$

By using equation (2), the time needed for the car to come to rest is calculated as follows:

$\begin{gathered} v(t)=(31.3ms^{-1})_{}+(-1.6ms^{-2})t=0 \\ t=\frac{31.3ms^{-1}}{1.6ms^{-2}}=19.56s \\ t=19.563s \end{gathered}$

By using equation (1), The total distance traveled in that time would be as:

$\begin{gathered} x(19.563s)=_{}(31.3ms^{-1})\cdot(19.563s)+\frac{1}{2}(-1.6ms^{-2})\cdot(19.563s)^2\Rightarrow(1) \\ x(19.563s)=612.31-306.17=306.14m \\ \therefore\Rightarrow \\ x(19.563s)=306.14m \end{gathered}$

The revolutions taken by the tire before the car comes to rest would be:

$\begin{gathered} C=2\pi\cdot(0.31m)=1.95m \\ R=\frac{x(19.563s)}{C}=\frac{306.14m}{1.95m}=156.99\operatorname{Re}v \\ R=156.99\operatorname{Re}vs \end{gathered}$

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2 years ago

Contrast situations where work is done with different amounts of force to situations where no work is done such as standing stil

uranmaximum [27]

Picking up a sheet of paper . . . work done with small force
Picking up a glass of water . . . work done with moderate force
Picking up a huge boulder . . . work done with a great tremendous force
=================================
Standing still . . .
Holding your tongue out as far as it will go . . .
Holding your arm over your head for 3 days . . .
Holding a huge boulder motionless over your head . . .
Pushing on a brick wall . . .
Pushing as hard as you can against a truck with the wheels locked . . .
. . . . . No work done at all, because the force doesn't move through a distance.

<u>Work done = (force) times (distance)</u>

If the force doesn't move, then the distance is zero, and the work done is zero.

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3 years ago

Jupiter’s strength of gravity is greater than Earth’s strength of gravity.

Alex Ar [27]

Answer:

................True

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3 years ago

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