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NISA [10]
4 years ago
15

A boat travels in a straight path that is 25° west of north. Which describes the values of the west and north components of the

boat’s displacement?
Both components are positive numbers. Both components are negative numbers. The west component is a negative number, and the north component is a positive number. The west component is a positive number, and the north component is a negative number
Physics
2 answers:
goldfiish [28.3K]4 years ago
5 0
The answer to the question would be the second choice: <span>The west component is a negative number, and the north component is a positive number. It can be based upon in a Cartesian coordinate system wherein the coordinate is located in the second quadrant. </span>
skelet666 [1.2K]4 years ago
5 0

Answer:

The west component is a negative number, and the north component is a positive number.

Explanation:

For this problem, we take the standard Cartesian axis, so that:

- along the vertical axis, the north direction is positive, and the south direction is negative

- along the horizontal axis, the east direction is positive, and the west direction is negative

The boat travels in a direction which is 25° west of north. This means that its vertical component is in the north direction, while the horizontal component is in the west direction. Since north = positive and west = negative, the correct option is

The west component is a negative number, and the north component is a positive number.

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Answer: A

Explanation:

Lunar eclipses work the same way in a different order: Moon, Earth and Sun all on a line. In this case the Earth's shadow hides the Moon from view.

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Two long conducting cylindrical shells are coaxial and have radii of 20 mm and 80 mm. The electric potential of the inner conduc
romanna [79]

Answer:

a) The speed of the electron as it reaches the inner conductor is closest to:

v = 1.45 × 10⁷m/s

b) The electric field magnitude between the cylinders is

E = 10,000V/m

Explanation:

given

inner radius of the cylinder r₁ = 20mm = 0.02m

outter radius of the cylinder r₂ = 80mm = 0.08m

potential difference V= 600V

mass of electron = 9.1×10⁻³¹kg

charge on electron = 1.6×10⁻¹⁹C

calculating the work done in bringing electron at inner conductor is

W =\frac{1}{2}mv^{2}

note:

V = \frac{W}{q}

∴W = (ΔV)q

(ΔV)q = \frac{1}{2}mv^{2}

(600)1.6×10⁻¹⁹ = ¹/₂ × 9.1×10⁻³¹ × v²

v² ≈ 2.11 × 10¹⁴

v = 1.45 × 10⁷m/s

According to the energy conservation law, the total energy of an isolated system is always constant.  

The energy of an isolated system can neither be created nor be destroyed, it can only convert one form to another form.

∴ the maximum electric field

E = ΔV/d

E = 600/d

where d is the distance between the two points

where d = 0.06m

E = 600/0.06

E = 10,000V/m

Note: the electric field due to the potential difference between to points depends upon the potential difference V and the distance between both points d.

5 0
3 years ago
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