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NISA [10]
3 years ago
15

A boat travels in a straight path that is 25° west of north. Which describes the values of the west and north components of the

boat’s displacement?
Both components are positive numbers. Both components are negative numbers. The west component is a negative number, and the north component is a positive number. The west component is a positive number, and the north component is a negative number
Physics
2 answers:
goldfiish [28.3K]3 years ago
5 0
The answer to the question would be the second choice: <span>The west component is a negative number, and the north component is a positive number. It can be based upon in a Cartesian coordinate system wherein the coordinate is located in the second quadrant. </span>
skelet666 [1.2K]3 years ago
5 0

Answer:

The west component is a negative number, and the north component is a positive number.

Explanation:

For this problem, we take the standard Cartesian axis, so that:

- along the vertical axis, the north direction is positive, and the south direction is negative

- along the horizontal axis, the east direction is positive, and the west direction is negative

The boat travels in a direction which is 25° west of north. This means that its vertical component is in the north direction, while the horizontal component is in the west direction. Since north = positive and west = negative, the correct option is

The west component is a negative number, and the north component is a positive number.

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The correct answer is Option (C) distance and time

Explanation:

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3 years ago
An electric fan is turned off, and its angular velocity decreases uniformly from 500 rev/min to 200 rev/min in 4.00 s.
Veseljchak [2.6K]

Answer:

a) -1.25 rev/s² and 23.3 rev

b)  2.67s

Explanation:

a) ωФ_o_z = (500 rev/min)(1min/ 60s) => 8.333 rev/s

ωФ_Z= (200 rev/min)(1min/ 60s) => 3.333rev/s

time 't'= 4 s

angular acceleration 'αФ_Z'=?

constant angular acceleration equation is given by,

ωФ_Z= ωФ_o_z + αФ_Zt

αФ_Z= (ωФ_Z - ωФ_o_z )/t => (3.333-8.333)/4

αФ_Z= -1.25 rev/s²

θ-θФ_o = ωФ_o_z t + 1/2αФ_Zt²

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      =23.3 rev

b) ωФ_Z=0   (comes to rest)

ωФ_o_z = 3.333 rev/s

αФ_Z= -1.25 rev/s²

ωФ_Z= ωФ_o_z + αФ_Zt

t= (ωФ_Z - ωФ_o_z)/αФ_Z => (0- 3.333)/-1.25

t= 2.67s

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