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Allushta [10]
3 years ago
11

A toaster draws 8 A of current with a voltage of 120 V. Which is the power used by the toaster

Physics
1 answer:
Tatiana [17]3 years ago
7 0

Power = (voltage) x (current) =

               (120 V)  x  (8 A)      =  <em>960 watts</em>


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Una barra metálica de 2 m de largo recibe una fuerza que lo provoca una alargamiento o variación en su longitud de 0.3 cm ¿Cuál
Elan Coil [88]

Answer:

La deformación unitaria lineal experimentada por la barra es 1.5\times 10^{-3}.

Explanation:

De la Mecánica de Materiales sabemos que la deformación unitaria lineal es la razón de la variación de la longitud con respecto a su longitud inicial. Al asumirse que la variación longitudinal es muy pequeña con respecto a la longitud inicial, se puede utilizar la siguiente ecuación:

\epsilon = \frac{\Delta l}{l_{o}} (Eq. 1)

Donde:

\epsilon - Deformación unitaria, adimensional.

\Delta l - Cambio longitudinal, medido en metros.

l_{o} - Longitud inicial, medida en metros.

Si conocemos que \Delta l = 3\times 10^{-3}\,m y l_{o} = 2\,m, entonces la deformación unitaria lineal es:

\epsilon = \frac{3\times 10^{-3}\,m}{2\,m}

\epsilon = 1.5\times 10^{-3}

La deformación unitaria lineal experimentada por la barra es 1.5\times 10^{-3}.

3 0
4 years ago
“Relative” is an important word. Block L of mass mL = 1.90 kg and block R of mass mR = 0.460 kg are held in place with a compres
Evgesh-ka [11]

Answer:m

R

​

ν

R

​

+m

L

​

ν

L

​

=0   ⇒    (0.500kg)ν

R

​

+(1.00kg)(−1.20m/s)=0

which yields ν

R

​

=2.40m/s . Thus , Δx=ν

R

​

t=(2.40m/s)(0.800s)=1.92m .

(b) Now we have m

R

​

ν

R

​

+m

L

​

(ν

R

​

−1.20m/s)=0 which yields

        ν

R

​

=

m

L

​

+m

R

​

(1.2m/s)m

L

​

​

=

1.00kg+0.500kg

(1.20m/s)(1.00kg)

​

=0.800m/s .

Consequently , Δx=ν

R

​

t=0.640m .

Explanation:

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2 years ago
WILL MARK BRAINLIEST !!!
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Answer:

P waves are a type of seismic wave that is characterized by being a longitudinal mechanical wave, which means that the medium through which they travel is alternately compressed and dilated in the<u> same direction of propagation</u>. This means they propagate in a similar way to the sound.

These waves are faster than the S waves, so when an earthquake occurs these waves <u>are the first to be recorded by the seismograph</u>. They can also travel through any type of material (solid, liquid or gaseous), this means they are able to <u>travel through solid rocks as well as in oceans or volcanic magma and are even able to be </u><u>transmitted through the atmosphere</u>, that is why they are sometimes perceived by people and animals as a deep sound.

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3 years ago
Solution A has a specific heat of 2.0 J/g◦C. Solution B has a specific heat of 3.8 J/g◦C. If equal masses of both solutions start
fgiga [73]

Answer: 2. Solution A attains a higher temperature.

Explanation: Specific heat simply means, that amount of heat which is when supplied to a unit mass of a substance will raise its temperature by 1°C.

In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.

Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.

<em>We have a formula for such condition,</em>

Q=m.c.\Delta T.....................................(1)

where:

  • \Delta T= temperature difference
  • Q= heat energy
  • m= mass of the body
  • c= specific heat of the body

<u>Proving mathematically:</u>

<em>According to the given conditions</em>

  • we have equal masses of two solutions A & B, i.e. m_A=m_B
  • equal heat is supplied to both the solutions, i.e. Q_A=Q_B
  • specific heat of solution A, c_{A}=2.0 J.g^{-1} .\degree C^{-1}
  • specific heat of solution B, c_{B}=3.8 J.g^{-1} .\degree C^{-1}
  • \Delta T_A & \Delta T_B are the change in temperatures of the respective solutions.

Now, putting the above values

Q_A=Q_B

m_A.c_A. \Delta T_A=m_B.c_B . \Delta T_B\\\\2.0\times \Delta T_A=3.8 \times \Delta T_B\\\\ \Delta T_A=\frac{3.8}{2.0}\times \Delta T_B\\\\\\\frac{\Delta T_{A}}{\Delta T_{B}} = \frac{3.8}{2.0}>1

Which proves that solution A attains a higher temperature than solution B.

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