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Sedaia [141]
3 years ago
11

Beginning with NADH, track the flow of electrons through the ETC. A. Complex I, Complex II, Complex III, Complex IV B. Complex I

I, Ubiquinone, Complex III, Cytochrome C, Complex IV. C. Complex III, Ubiquinone, Complex II, Cytochrome C, Complex IV, Oxygen D. Complex I, Ubiquinone, Complex III, Cytochrome C, Complex IV, Oxygen.
Biology
1 answer:
Vilka [71]3 years ago
5 0

Answer:

D. Complex I, Ubiquinone, Complex III, Cytochrome C, Complex IV, Oxygen.

Explanation:

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Strontium-90 has a half life of 29 years, how much strontium-90 is left from the Chicago pile reactor that was active around 87
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Answer:

The answer is below

Explanation:

The half life of a substance is the time required by that substance to reduce to half of its initial value. The half life is calculated using the formula:

N(t)=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\where\ N(t)=quantity\ of\ substance \ remaining, N_o=initial\ quantity\\of\ substance, t=time\ and \ t_\frac{1}{2}=half\ life\ of\ substance

Given that t = 87 years, half life = 29 years, therefore the quantity of strontium-90 left is:

N(t)=N_o(\frac{1}{2} )^\frac{87}{29} \\\\N(t)=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\N(t)=N_o(\frac{1}{2} )^3\\\\N(t)=\frac{1}{8} N_o

That is one-eight of Strontium 90 would be left after 87 years

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