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Nostrana [21]
4 years ago
6

40 POINTS!!!! what is the coordinates of x+y=6?

Mathematics
2 answers:
il63 [147K]4 years ago
4 0
Here, your equation is x + y = 6

In order to calculate coordinates, put x = 0, 
0 + y = 6, 
y = 6

Now, put y = 0, x + 0 = 6
x = 6

So, Your Coordinates would be: (0, 6) & (6, 0)

Hope this helps!
irakobra [83]4 years ago
3 0
Solve for x + y = 6.


<span>your coordinates are (0, 6) ;(6, 0)!! Hope this helps</span>
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Brenna had a gross income of $2158.22 during each pay period in 2010. If she got paid monthly, how much of her pay was deducted
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FICA stands for Federal Insurance Contributions Act and FICA taxes are deductions from gross earnings at a rate of 7.65%. If Brenna earns monthly at a gross of $2158.22, then her deduction for FICA is $165.10383 which is 7.65% from her gross income ($2158.22 x 0.0765).
8 0
4 years ago
Read 2 more answers
Future Sporting Goods has a market-share factor of 25% of the retail business in Martin County. The total estimated sporting goo
Anastasy [175]

multiply 15430000 by 25%

25% = 0.25

15430000 x 0.25 = 3857500

7 0
3 years ago
Write the equation of the line that passes through the given points.<br> (0.-6) and (7.0)
ahrayia [7]
<h2>Answer:    y =  ⁶/₇ ( x  -  7 )</h2>

Step-by-step explanation:

The slope of tghe line (m) = (y₂ - y₁) ÷ (x₂ - x₁)

                                          =  (- 6 -0) ÷ ( 0 - 7)

                                          =    ⁶/₇

We can now use the point-slope form to write the equation for this line:

y - y₁ = m(x - x₁) where (x₁ , y₁) = (7 , 0)

              y =  ⁶/₇ ( x  -  7 )

6 0
3 years ago
Can i get some help? can you solve the area to a trapozoid?
Aliun [14]

Answer:

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8 0
3 years ago
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Need help asap please
jonny [76]

Answer:

B. x= 4

Step-by-step explanation:

We know that,

The result for the intersection of the secant and the tangent is given by by the figure below,

UV^{2}=UX\times UY

According to the question, we have,

8^{2}=x(12+x)

i.e. 64=12x+x^2

i.e. x^2+12x-64=0

Now, the solution of a quadratic equation ax^2+bx+c=0 is given by, x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

So, we get,

x^2+12x-64=0 implies a= 1, b= 12 and c= -64.

Thus, the solution is given by,

x=\frac{-12\pm \sqrt{12^{2}-4\times 1\times (-64)}}{2\times 1}

i.e. x=\frac{-12\pm \sqrt{144+256}}{2}

i.e. x=\frac{-12\pm \sqrt{400}}{2}

i.e. x=\frac{-12\pm 20}{2}

i.e. x=\frac{-12-20}{2} and i.e. x=\frac{-12+20}{2}

i.e. x=\frac{-32}{2} and i.e. x=\frac{8}{2}

i.e x= -16 and x= 4.

Since, length cannot be negative.

So, we have, x= 4.

8 0
3 years ago
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