Ask question

Ask question

All categories

3 years ago

5

A golfer hits the 0.075 Kg ball with a force F. After the club hits the ball with force F, the ball starts moving at 70m/s. If t

he impact between the ball and the club lasted only for 0.003 seconds, calculate the force F.

1 answer:

Alisiya [41]3 years ago

4 0

The equation we want to use is F = ma

mass x acceleration = Force

0.075 kg x 70 m/s = 5.25 Newtons

You might be interested in

Hi! I need help quick!

11Alexandr11 [23.1K]

Answer:

We usually travel in January or Feb for our tropical get-a-way. For those of you that have traveled in the fall and winter...

What is the real difference...Like in the floral and fauna, weather, and the capacity of the resorts between these 2 times of the year.

7 0

2 years ago

Noah is loading the ark and the last animal on board is a stubborn 1500-kg elephant who refuses to budge. Noah and his family pu

Oxana [17]

The coefficient of sliding friction is 0.514

Explanation:

We start by writing the equations of motion of the elephant along the two directions, parallel and perpendicular, to the incline.

Along the parallel direction we have:

$F- mg sin \theta - \mu_k R = ma$ (1)

where :

F = 10,000 N is the force applied by Noah

$mg sin \theta$ is the component of the weight parallel to the incline, where:

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

$\theta=10^{\circ}$ is the angle of incline

$\mu_k R$ is the force of friction, where:

$\mu_k$ is the coefficient of friction

R is the normal reaction

and a is the acceleration

Perpendicular direction:

$R-mg cos \theta =0$ (2)

where $mg cos \theta$ is the component of the weight perpendicular to the incline

From (2) we find

$R=mg cos \theta$

And substituting into (1)

$F-mg sin \theta - \mu_k mg cos \theta = ma$

We know that the elephant moves at constant speed, so the acceleration is zero:

a = 0

So the equation becomes

$F-mg sin \theta - \mu_k mg cos \theta=0$

And we can re-arrange it to find the coefficient of friction:

$F-mg sin \theta - \mu_k mg cos \theta=0\\\mu_k = \frac{F-m g sin \theta}{mg cos \theta}=\frac{10000-(1500)(9.8)(sin 10)}{(1500)(9.8)(cos 10)}=0.514$

Learn more about friction and inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

4 0

3 years ago

We have compared the Terrestrial Planets and the Giant or Jovian Planets, but when we look at the 4 Giant Planets we can see tha

Ksivusya [100]

Answer:

i. Magnetic fields

ii. All 4 planets in appearance have deeper atmospheres and darker cloud.

iii. All the 4 Jovian planets rotates very quickly, with a range of 10 to 17 hours.

Explanation:

The Jovian planets is different from terrestrial planets in so many ways. The Jovian planets includes Jupiter , Saturn, Uranus and Neptune.

The major similarities shared by all of these 4 planets includes

i. Magnetic fields: Each of this Jovian planets have a strong magnetic field and are generated by electric currents in its rapidly sniping interior. The magnetosphere which is the region at which the planet magnetic field dominates is far more stronger in Jupiter than other Jovian planets . Although the magnetic field of Saturn , Neptune and Uranus works in similar way to Jupiter but are less stronger.

ii. All 4 planets in appearance have deeper atmospheres and darker cloud. The uppermost clouds of Jupiter and Saturn has more of ammonia crystals .The upper cloud of Neptune is composed of methane, The cloud of Uranus is deep.

iii. All the 4 Jovian planets rotates very quickly, with a range of 10 to 17 hours. The rotation period of Jupiter is the shortest among the Jovian planets which is around 9 hours 55 minutes. The rotation period of Neptune and Uranus take longer time than the other 2 Jovian planets( a little above 17 hours).

4 0

4 years ago

A motorboat traveling on a straight course slows

never [62]

Answer:

2.572 m/s²

Explanation:

Convert the given initial velocity and final velocity rates to m/s:

65 km/h → 18.0556 m/s
35 km/h → 9.72222 m/s

The motorboat's displacement is 45 m during this time.

We are trying to find the acceleration of the boat.

We have the variables v₀, v, a, and Δx. Find the constant acceleration equation that contains all four of these variables.

v² = v₀² + 2aΔx

Substitute the known values into the equation.

(9.72222)² = (18.0556)² + 2a(45)
94.52156173 = 326.0046914 + 90a
-231.4831296 = 90a
a = -2.572

The magnitude of the boat's acceleration is |-2.572| = 2.572 m/s².

3 0

3 years ago

A lamp draws a current of 0.50 A when it is connected to a 120 V source? What is the resistance of the lamp?

emmainna [20.7K]

Given,
Current (I) = 0.50A
Voltage (V) = 120 volts
Resistance (R) =?
We know that:-
Voltage (V) = Current (I) x Resistance (R)
→Resistance (R) = Voltage (V) / Current (I)
= 120/0.50
= 24Ω
∴ Resistance (R) = 24Ω

8 0

3 years ago

Read 2 more answers