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3 years ago

A motorboat traveling on a straight course slows

Physics

1 answer:

never [62]3 years ago

3 0

Answer:

2.572 m/s²

Explanation:

Convert the given initial velocity and final velocity rates to m/s:

65 km/h → 18.0556 m/s
35 km/h → 9.72222 m/s

The motorboat's displacement is 45 m during this time.

We are trying to find the acceleration of the boat.

We have the variables v₀, v, a, and Δx. Find the constant acceleration equation that contains all four of these variables.

v² = v₀² + 2aΔx

Substitute the known values into the equation.

(9.72222)² = (18.0556)² + 2a(45)
94.52156173 = 326.0046914 + 90a
-231.4831296 = 90a
a = -2.572

The magnitude of the boat's acceleration is |-2.572| = 2.572 m/s².

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A cannon with a muzzle speed of 1 000 m/s is used to start an avalanche on a mountain slope. The target is 2 000 m from the cann

Nataliya [291]

Answer:

∅ = 89.44°

Explanation:

In situations like this air resistance are usually been neglected thereby making g= 9.81 m/ $s^{2}$

Bring out the given parameters from the question:

Initial Velocity ( $V_{1}$ ) = 1000 m/s

Target distance (d) = 2000 m

Target height (h) = 800 m

Projection angle ∅ = ?

Horizontal distance = $V_{1x}$ tcos ∅ .......................... Equation 1

where $V_{1x}$ = velocity in the X - direction

t = Time taken

Vertical Distance = y = $V_{1y}$ t - $\frac{1}{2}$ g $t^{2}$ ................... Equation 2

Where $V_{1y}$ = Velocity in the Y- direction

t = Time taken

$V_{1y}$ = $V_{1}$ sin∅

Making time (t) subject of the formula in Equation 1

t = d/( $V_{1x}$ cos ∅)

t = $\frac{2000}{1000coso}$ = $\frac{2}{cos0}$ = $\frac{d}{cos o}$ ...................Equation 3

substituting equation 3 into equation 2

Vertical Distance = d = $V_{1y}$ $\frac{d}{cos o}$ - $\frac{1}{2}$ g $\frac{2}{cos0} ^{2}$

Vertical Distance = h = sin∅ $\frac{d}{cos o}$ - $\frac{1}{2}$ g $\frac{2}{cos0} ^{2}$

Vertical Distance = h = dtan∅ - $\frac{1}{2}$ g $\frac{2}{cos0} ^{2}$

Applying geometry

$\frac{1}{cos o}$ = $tan^{2} o$ + 1

Vertical Distance = h = d tan∅ - 2 g ( $tan^{2} o$ + 1)

substituting the given parameters

800 = 2000 tan ∅ - 2 (9.81)( $tan^{2} o$ + 1)

800 = 2000 tan ∅ - 19.6( $tan^{2} o$ + 1) Equation 4

Replacing tan ∅ = Q .....................Equation 5

In order to get a quadratic equation that can be easily solve.

800 = 2000 Q - 19.6 $Q^{2}$ + 19.6

Rearranging 19.6 $Q^{2}$ - 2000 Q + 780.4 = 0

$Q_{1}$ = 101.6291

$Q_{2}$ = 0.411

Inserting the value of Q Into Equation 5

tan ∅ = 101.63 or tan ∅ = 0.4114

Taking the Tan inverse of each value of Q

∅ = 89.44° ∅ = 22.37°

4 0

3 years ago

An object is traveling at 15 m/s and then after 5 seconds ends up traveling at 10 m/s. Calculate the speeds acceleration rate. W

SSSSS [86.1K]

Answer:

1) a = -1 m/s²

2) v = 12 m/s

Explanation:

Given,

The initial velocity of the object, u = 15 m/s

The final velocity of the object, v = 10 m/s

The time taken by the object to travel is, t = 5 s

Using the first equation of motion

a = (v - u) / t

Substituting the values

a = (10 - 15) / 5

= -1 m/s²

The negative sign indicates the body is decelerating

The acceleration of the object is, a = -1 m/s²

The speed of the object after 2 seconds

From the above equations of motion

v = 15 + (-1) 2

= 12 m/s

Hence, the speed of the object after 2 seconds is, v = 12 m/s

7 0

4 years ago

Consider an electrical transformer that has 10 loops on its primary coil and 20 loops on its secondary coil. What is the current

rusak2 [61]

Answer:

C. 2.5 A

Explanation:

Transformer: A transformer is an electromechanical device that is used to change the voltage of an alternating current.

The current and the number of loops in a transformer is related as shown below

Ns/Np = Ip/Is........................... Equation 1

Where Ns = Secondary loop, Np = primary loop, Ip = primary current, Is = secondary current.

Making Is the subject of the equation

Is = NpIp/Ns........................ Equation 2

Given: Np = 10 loops, Ns = 20 loops, Ip = 5.0 A.

Substitute into equation 2

Is = (10×5.0)/20

Is = 50/20

Is = 2.5 A.

Hence the current in the primary coil = 2.5 A.

The right option is C. 2.5 A

6 0

3 years ago

Which physical property of matter depends on push

liberstina [14]

Answer:

I would say contact forces

Explanation:

This questions is kind of missing some info but I do know that contact forces need to be either pushed or pulled for a force to happen.

Hope this helped

4 0

3 years ago

A solution is known as a homogeneous mixture because _[blank]_.

alekssr [168]

Answer:

The solute fully dissolves in the solvent

Explanation:

This is because for a solution to be called a homogeneous mixture, all the solute must be dissolved in the solvent, without the particles of the solute being visible in the solvent.

8 0

3 years ago