Answer:
Step-by-step explanation:
From the given information:
a) To express the weekly profit as a function of price
Cost =C(q) = 1500 + 10q
Revenue = p×q = (50 − 0.1q)×q = 50q - 0.1q²
Revenue = 50q - 0.1q²
Weekly profit = Revenue - Cost
P(q) = (50q -0.1q²) - (1500 + 10q)
P(q)= -0.1 q² + 40 q - 1500
However, q = 500 - 10 p using p = 50 − 0.1q
P= -0.1 (500 - 10 p)² + 40 (500 - 10 p) - 1500
P= -10 p² + 600 p - 6500
b)
The price at which the bottle of the wine must be sold to realise a maximum profit can be determined by finding the derivative and then set it to 0
P' = 0
= -20p+600 = 0
20p = 600
p = 600/20
p = $30
c)
The maximum profit that can be made by the producer is:
P= -10(30)² + 600(30) - 6500
P = - 9000 + 18000 - 6500
P = $2500
X+46.9=61.5
-46.9 -46.9
------------------------
x=14.6
There is no solutions.
6 ( y + 8 ) = 3 ( 2y - 7 )
6y + 48 = 6y - 21
-48 -48
6y = 6y - 27
+27 +27
33y÷33 = 6y÷33
y=2/11 or 0.18
Hope this helps!
Answer: 76
Step-by-step explanation:
3 * 2 = 6
6* 2 = 12
2 * 32 = 64
12 + 64 = 76