Answer:
Step-by-step explanation:
Given that:
To bet $5 that the outcome is any one of these five possibilities: 0, 00, 1, 2, 3.
Let Y represent the Amount of net profit
Then, Y= {-5, 30}
The probability distribution of Y is:
Y -5 30
P(Y=y)

a) The expected value of X is given by:
![E[Y] =\sum y P(Y=y)= 30*\dfrac{5}{38}-5*\dfrac{33}{38}](https://tex.z-dn.net/?f=E%5BY%5D%20%3D%5Csum%20y%20P%28Y%3Dy%29%3D%2030%2A%5Cdfrac%7B5%7D%7B38%7D-5%2A%5Cdfrac%7B33%7D%7B38%7D)


b)
On a bet of $5 on the number 25 we are expected to loose 24 cents.
While on a $5 bet that the outcome is any one of the numbers 0,00, or 1 we are expected to loose 39 cents.
Hence, $5 bet on the number 27 is better. Because the expected loss is less in this bet
Hey there!
Let's start by finding what 1% of 210 is.
This can be done by dividing 210 by 100, since 1% is the same as 1/100 of something.
210 ÷ 100 = 2.1
To find 36%, we can multiply 2.1 by 36.
2.1 x 36 = 75.6
So, 36% of 201 is 75.6.
Hope this helps!
Answer:
90
Step-by-step explanation:
600(.15) = 90