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MrRa [10]
3 years ago
11

Find the equation of the line (in slope intercept form) if the slope of the line is (-5/6) and the point (12,9) is a point on th

e line
Mathematics
1 answer:
horsena [70]3 years ago
6 0
(y=mx+b) Where m is slope and b is y-int.
y=-5/6x-1
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The correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot

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the given equation is 5y + 4 =(x+3)^{2}  + \frac{1}{2}

Therefore we can write 5y\hspace{0.1cm} = (x+3)^{2} + \frac{1}{2} - 4  \hspace{0.3cm}   \Rightarrow  \hspace{0.2cm}  5y = (x+3)^{2} - \frac{7}{2}   \hspace{0.3cm} \Rightarrow \hspace{0.3cm}  y = \frac{(x+3)^{2}}{5} - \frac{7}{10}

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Therefore we get

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y = \pm \sqrt{5 (x + \frac{7}{10} )} \hspace{0.1cm} - \hspace{0.1cm} 3 \hspace{0.1cm} \Rightarrow\hspace{0.1cm}  y =  \pm \sqrt{5x + \frac{7}{2} }  - \hspace{0.1cm} 3 \hspace{0.1cm}

Therefore the correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot , y =  \pm \sqrt{5x + \frac{7}{2} }  - \hspace{0.1cm} 3 \hspace{0.1cm}

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