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n200080 [17]
2 years ago
8

Suppose you were told that the above reaction was a substitution reaction but you were not told the mechanism. Evaluate the foll

owing categories to determine the reaction mechanism and then draw the structure of the major organic product.Type of alkyl halide: _________ (methyl, primary, primary benzyl, primary allyl, secondary, secondary benzyl, secondary allyl, tertiary, tertiary benzyl, tertiary allyl.)Type of nucleophile: _________ (good, moderate, poor.)Solvent: _________ (protic, aprotic.)Is the product racemic? _____ (yes, no.)

Chemistry
1 answer:
Zarrin [17]2 years ago
3 0

Answer:

The alkyl halide is secondary

The nucleophile is a poor nucleophile

The solvent is a protic solvent

The product is racemic

Explanation:

The reaction is shown in the image attached.

Alkyl halides undergo nucleophilic substitution by two mechanisms; SN1 and SN2. The particular mechanism that applies depends on;

I) structure of the alkyl halide

ii) nature of the nucleophile

iii) nature of the solvent

Looking at the reaction under review, we can see from the structure that the alkyl halide is a secondary alkyl halide. A secondary alkyl halide may undergo substitution via SN1 or SN2 mechanism depending on the conditions of the reaction.

If the nucleophile is poor, and the solvent is protic, SN1 mechanism is favoured over SN2 mechanism. Since CH3CH2OH is a poor nucleophile and ethanol is a protic solvent, we expect the reaction to proceed via SN1 mechanism leading to the formation of a racemic product.

The organic product is also shown in the second image attached.

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what layers of protection can be used tot detect and respond to abnormal reactions or process conditions
alex41 [277]

In the body, the main protective layer is known as the epithelium, this can be found in the skin as well as other organs such as the lungs.

The body is often exposed to external factors that can damage it; due to this, throughout evolution, most animals and multicellular organisms have developed protective mechanisms.

In the case of humans and other animals, the protective layer is known as the epithelium, which is composed of epithelial cells. This protective layer can be found internally and externally.

External layer: This is the first protective layer, commonly known as skin, this layer protects the inner organs from extreme temperatures, changes in pressure, etc.

Internal layer: Organs such as the lungs or the ones in the gastrointestinal system are all covered by a thin epithelial layer that helps each organ to be protected.

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5 0
2 years ago
There are two isotopes of boron: boron-10 and boron-11. Explain, in terms of weighted average atomic mass, the difference in per
Zolol [24]

Answer:

Percent abundance of  B¹⁰ is 19.9% and  B¹¹ is 80.1%.

The weighted average atomic mass of boron is 10.811 amu.

Explanation:

We know that average atomic mass of Boron is 10.811 amu and there are two isotopes of boron B¹⁰ (10.012938) and B¹¹ (11.009305)

We will determine the percent abundance of each isotopes.

First of all we will set the fraction for both isotopes B¹⁰ and  B¹¹.

X for the isotopes having mass 11.009305 amu.

1-x for isotopes having mass 10.012938 amu.

The average atomic mass of Boron is 10.811 amu

we will use the following equation,

11.009305x +  10.012938  ( 10.012938 -x) = 10.811

11.009305x +  10.012938 -  10.012938 x = 10.811

11.009305x   -  10.012938 x = 10.811 -  10.012938

0.996367x = 0.798062

x= 0.798062 / 0.996367

x= 0.800972

Percent abundance of B¹¹.

0.800972 × 100 = 80.1 %

80.1 % is abundance of B¹¹ because we solve the fraction x.

now we will calculate the abundance of B¹⁰.

(1-x)

1-0.800972 =0.199

Percent abundance of  B¹⁰.

0.199 × 100=  19.9%

19.9% for B¹⁰.

Now we can calculate the average atomic mass of boron.

Formula:

Average atomic mass = [mass of isotope× its abundance] + [mass of isotope× its abundance] +...[ ] / 100

Now we will put the values in formula.

Average atomic mass = [19.9 × 10.012938] + [80.1 × 11.009305] / 100

Average atomic mass = 199.2575 + 881.8453 / 100

Average atomic mass = 10.811 amu

8 0
3 years ago
Given the following reaction and data, A + B → Products
natima [27]

Answer:

a. Rate = k×[A]

b. k = 0.213s⁻¹

Explanation:

a. When you are studying the kinetics of a reaction such as:

A + B → Products.

General rate law must be like:

Rate = k×[A]ᵃ[B]ᵇ

You must make experiments change initial concentrations of A and B trying to find k, a and b parameters.

If you see experiments 1 and 3, concentration of A is doubled and the Rate of the reaction is doubled to. That means a = 1

Rate = k×[A]¹[B]ᵇ

In experiment 1 and to the concentration of B change from 1.50M to 2.50M but rate maintains the same. That is only possible if b = 0. (The kinetics of the reaction is indepent to [B]

Rate = k×[A][B]⁰

<h3>Rate = k×[A]</h3>

b. Replacing with values of experiment 1 (You can do the same with experiment 3 obtaining the same) k is:

Rate = k×[A]

0.320M/s = k×[1.50M]

<h3>k = 0.213s⁻¹</h3>

6 0
3 years ago
Desclony When Fe(NO3)2 dissolves in water, what particles are present in the solution?​
Hitman42 [59]

Answer:

hjfhgjgjgjghgjgjhgjhhjh

3 0
2 years ago
A bond formed when atoms transfer elentron is a bond
lubasha [3.4K]
Ionic bonds involve a cation and an anion. The bond is formed when an atom, typically a metal, loses an electron or electrons, and becomes a positive ion, or cation. Another atom, typically a non-metal, is able to acquire the electron(s) to become a negative ion, or anion.

One example of an ionic bond is the formation of sodium fluoride, NaF, from a sodium atom and a fluorine atom. In this reaction, the sodium atom loses its single valence electron to the fluorine atom, which has just enough space to accept it. The ions produced are oppositely charged and are attracted to one another due to electrostatic forces.
5 0
3 years ago
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