Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen 
if it occupies 31.6 mL at 
.
Explanation:
Given : Mass of oxygen = 0.023 g
Volume = 31.6 mL
Convert mL into L as follows.
Temperature = 
As molar mass of 
is 32 g/mol. Hence, the number of moles of are calculated as follows.
Using the ideal gas equation calculate the pressure exerted by given gas as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the value into above formula as follows.
Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen if it occupies 31.6 mL at .
?? Is that the whole question?
Yes, it will be worthwhile to investigate finding a catalyst to use in this reaction under standard conditions because it is negative.
<h3>What is a Catalyst?</h3>
This is a substance which speeds up the rate of a chemical reaction by lowering the activation energy.
ΔG being negative indicates a a slow reaction which is why a catalyst under standard conditions should be used.
Read more about Catalyst here brainly.com/question/12507566
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Many homeowners treat their lawns with CaCO3(s) to reduce
the acidity of the soil. The net ionic equation for the reaction of CaCO3(s)
with a strong acid, HCl (I chose HCl because it is a strong acid) is CaCO3(s) +2
HCl(aq) → CaCl2(s) + H2O(aq) + CO2(g).
