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arlik [135]
3 years ago
15

Mrs. Sail's class wanted to observe a local pond. The class collected some pond water to analyze. When they placed a drop of the

water under a microscope, they saw many microorganisms in the water. The pond water looked clear when they collected it in the jar, so what could explain the presence of these organisms? A) They must have grown in the jar overnight. B) The microorganisms are too small to be seen with the naked eye. C) Somehow, the jar was contaminated on the way from the pond to the class. D) The microorganisms only inhabit a very small section of the lake, and the class got lucky.
Chemistry
2 answers:
olasank [31]3 years ago
8 0

B) the microorganisms are to small too see with the naked eye

LiRa [457]3 years ago
3 0

B. its more of a reliable answer because it's true. You cant see it with the naked eye if you had to put in under a microscope.



I might be wrong.

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The total volume of the gas produced, given the data from the question is 11.84 L

<h3>How to determine the mole of (NH₄)₂CO₃</h3>
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  • Molar mass of (NH₄)₂CO₃ = 96 g/mol
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Mole = mass / molar mass

Mole of (NH₄)₂CO₃ = 11.83 / 96

Mole of (NH₄)₂CO₃ = 0.123 mole

<h3>How to determine the volume of NH₃</h3>

Balanced equation

(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)

From the balanced equation above,

1 mole of (NH₄)₂CO₃ decomposed to produce 2 moles of NH₃

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0.123 mole of (NH₄)₂CO₃ will decompose to produce = 0.123 × 2 = 0.246 mole of NH₃

Thus, we can determine the volume of NH₃ produced by using the ideal gas equation as follow:

  • Temperature (T) = 22 °C = 22 + 273 = 295 K
  • Pressure (P) = 1.02 bar
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PV = nRT

Divide both side by P

V = nRT / P

V = (0.246 × 0.08314 × 295) / 1.02

Volume of NH₃ = 5.92 L

<h3>How to determine the volume of CO₂</h3>

Balanced equation

(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)

From the balanced equation above,

1 mole of (NH₄)₂CO₃ decomposed to produce 1 moles of CO₂

Therefore,

0.123 mole of (NH₄)₂CO₃ will also decompose to produce = 0.123 mole of CO₂

Thus, we can determine the volume of CO₂ produced by using the ideal gas equation as follow:

  • Temperature (T) = 22 °C = 22 + 273 = 295 K
  • Pressure (P) = 1.02 bar
  • Gas constant (R) = 0.08314 bar.L/Kmol
  • Number of mole (n) = 0.123 moles
  • Volume of CO₂ (V) =?

PV = nRT

Divide both side by P

V = nRT / P

V = (0.123 × 0.08314 × 295) / 1.02

Volume of CO₂ = 2.96 L

<h3>How to determine the volume of H₂O</h3>

Balanced equation

(NH₄)₂CO₃ -> 2NH₃(g) + CO₂(g) + H₂O(g)

From the balanced equation above,

1 mole of (NH₄)₂CO₃ decomposed to produce 1 moles of H₂O

Therefore,

0.123 mole of (NH₄)₂CO₃ will also decompose to produce = 0.123 mole of H₂O

Thus, we can determine the volume of H₂O produced by using the ideal gas equation as follow:

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  • Pressure (P) = 1.02 bar
  • Gas constant (R) = 0.08314 bar.L/Kmol
  • Number of mole (n) = 0.123 moles
  • Volume of H₂O (V) =?

PV = nRT

Divide both side by P

V = nRT / P

V = (0.123 × 0.08314 × 295) / 1.02

Volume of H₂O = 2.96 L

<h3>How to determine the total volume of gas produced</h3>
  • Volume of NH₃ = 5.92 L
  • Volume of CO₂ = 2.96 L
  • Volume of H₂O = 2.96 L
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Total volume = 5.92 + 2.96 + 2.96

Total volume of gas = 11.84 L

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brainly.com/question/4147359

Learn more about stoichiometry:

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