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Ulleksa [173]
3 years ago
11

Chlorine has two isotopes. Chlorine-35 has an actual mass of 34.9689 u and chlorine-37 has a mass of 36.9659 u. In any sample of

chlorine atoms, 75.771% will be chlorine-35 and 24.229% will be chlorine 37. Calculate the average atomic mass of chlorine. 2. Copper has two isotopes. Copper-63, which has an atomic mass of 62.93 u and copper-65, which has an atomic mass of 64.93 u. In any sample of copper atoms, 69.1% will be copper-63 and 30.9% will be copper-65. Calculate the average atomic mass of naturally occurring copper.
Chemistry
1 answer:
pav-90 [236]3 years ago
5 0

Answer: 1. The average atomic mass of chlorine is 35.453u

2. The average atomic mass of copper is 63.5 u

Explanation:

Average atomic mass is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

1. For chlorine:

\text{Average atomic mass of chlorine }=(34.9689\times \frac{75.771}{100})+(36.9659\times \frac{24.229}{100})=35.453u

2.  For copper:

\text{Average atomic mass of chlorine }=(62.93\times \frac{69.1}{100})+(64.93\times \frac{30.9}{100})=63.5u

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alexgriva [62]

Answer:

29.256 torr.

Explanation:

Number of moles

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Water:

Converting g/ml to g/l,

1000 ml = 1 l

= 1 g/ml * 1000 ml/1l

= 1000 g/l

Mass = (density * volume)

= 1000*0.124

= 124 g.

Molar mass of water = (1*2) + 16

= 18 g/mol

Number of moles = mass /molar mass

= 126/18

= 6.89 mol

P°solution = xsolvent * P°solvent

Where,

xwater = xsolvent = mole fraction of water.

Mole fraction is defined as the number of moles of a component of a solution divided by the total number of moles present in that solution.

xwater = mole of water/total mole of solution

Total mole = 6.89 + 0.274

= 7.164 moles

xwater = 6.89/7.164

= 0.962

P°solution = xsolvent * P°solvent

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6 0
3 years ago
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Anna35 [415]

Answer:

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7 0
3 years ago
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mixas84 [53]

Answer:

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Explanation:

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3 years ago
A tank of water was contaminated with a colored dye (D). To determine the concentration of D, an analyst took 5.0-mL solution fr
alekssr [168]

Answer:

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Explanation:

Given data:

volume of sample solution ( volume of D ) = 5.0 mL

volume of added stock solution ( V1 ) = 5.0 mL

concentration of added stock solution ( N1 )  = 0.02 M

Total volume of concentration  ( V2 )= 10 mL = ( 5.0 mL + 5.0mL)

concentration of Total volume of sample ( C2 ) = 0.01

N2 = ( N1V1 ) / V2

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3 0
3 years ago
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Answer:

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