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liberstina [14]
3 years ago
13

What advice would you give to a person who handles hydrogen and oxygen in their workplace?I think I have an idea of what advice

to give, but I'm not entirely sure if it's correct. Please help!! I'm really bad at science.
Chemistry
1 answer:
finlep [7]3 years ago
3 0
Regard the principle of utilization of two gas.

Make a consistent control of hardware containing gas.

Make a consistent control of weight diminishing valves giving gas.

No smoking zone.
You might be interested in
5 Examples of simple salts
kolbaska11 [484]
<h3>Five Examples of Salts </h3>

  • Sodium Chloride.
  • Sodium chloride (NaCl) is the most common type of salt in our lives.
  • Potassium Dichromate. •
  • Potassium dichromate (K2Cr2O7) is an orange-colored salt composed of potassium, chromium and oxygen.
  • Calcium Chloride.
  • Sodium Bisulfate.
  • Copper Sulfate.

3 0
2 years ago
What information can be obtained from a chemical formula?
Nookie1986 [14]
The chemical properties, chemical reactivity
3 0
3 years ago
What is the silver ion concentration in a solution prepared by mixing 369 mL 0.373 M silver nitrate with 411 mL 0.401 M sodium c
LuckyWell [14K]

Answer:

[A g + ]  =  3.12 *10^-6 M

Explanation:

Step 1: Data given

Volume silver nitrate = 369 mL

Molarity silver nitrate = 0.373 M

Volume sodium chromate = 411 mL

Molarity sodium chromate = 0.401 M

The Ksp of silver chromate is 1.2 * 10^− 12

Step 2: The balanced equation

2 A g + ( a q )  +  C rO4^2-  ( a q )  →Ag2CrO4 (  s)

Step 3:

[Ag+]i = [AgNO3] * V1/(V1+V2) * 1 mol Ag+ / 1 mol AgNO3

[Ag+]i = 0.373 M * 0.369/ (0.369+0.411)

[Ag+]i = 0.176 M

[C rO4^2]i = [Ag2CrO4] * V2 /(V1+V2) * 1mol C rO4^2 / 1 mol Ag2CrO4

[C rO4^2i = 0.401 M * 0.411 / (0.369+0.411)

[C rO4^2]i = 0.211 M

Ksp = [Ag+]²[CrO4^2-] = 1.2 * 10^− 12

[CrO4^2-]f = [CrO4^2-]i - 0.5 * [Ag+]i

[CrO4^2-]f = 0.211 -0.088 = 0.123 M

1.2 * 10^− 12  = ( 2 x ) ²*( 0.123M + x )

[ C O 3^ −2] f  >>  x

1.2 * 10^− 12  = ( 2 x ) ²* 0.123M

x = 1.56 * 10^-6

[A g + ] f  = 2x = 3.12 *10^-6 M

,

4 0
3 years ago
17 points help asap!! :) thank youuuu :) Jeff is in a stationary school bus. Which is the best reference point for him to use to
3241004551 [841]

Answer:

The answer would be A

Hope this helps!!!

5 0
3 years ago
WHAT IS THE PERCENT BY VOLUME OF ETHANOL IN A SOLUTION THAT CONTAINS 35 mL ETHANOL IN 115 mL OF WATER?
Dmitry [639]
We need to first add both of the solution volumes together 35+115=150. Now we can divide the volume of the ethanol by the total volume 35/150=.233. To double check we can multiply the total volume by the percentage of ethanol by volume we got as a solution 150x.233=35. So the percentage by volume of ethanol in the solution is .233x100=23.3%.
3 0
3 years ago
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