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4 years ago

How many terms are in the expression 6y+3+y+4y+5

Mathematics

2 answers:

NikAS [45]4 years ago

6 0

Answer:

5 terms

Step-by-step explanation:

In an expression, a term can be a number, a variable, or a number and variable multiplied together. Terms are separated by addition or subtraction.

In the expression:

6y+3+y+4y+5

There are 5 terms. The 5 terms are:

1. 6y

2. 3

3. y

4. 4y

5. 5

We can simplify this expression by combining like terms. We can add the constants (just numbers) and the terms with variables being multiplied by numbers.

6y+3+y+4y+5

(6y+y+4y)+(3+5)

11y+(3+5)

11y+8

yawa3891 [41]4 years ago

4 0

Answer:

Step-by-step explanation:

The 5 terms in the expression are ...

If like terms were combined, the expression could be reduced to one with 2 terms:

11y +8

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Which is the additive inverse of the complex number -8+3i?

lawyer [7]

The additive inverse of a complex z is a complex number $-z,$ so that

$\mathsf{z+(-z)=-z+z=0+0i=0}$

Finding $-z:$

$\mathsf{z=-8+3i}\\\\\\ \mathsf{z+(-z)=0+0i}\\\\\ \mathsf{-8+3i+(-z)=0+0i}\\\\ \mathsf{-z=0+0i+8-3i}\\\\ \mathsf{-z=(0+8)+(0i-3i)}\\\\ \boxed{\begin{array}{c}\mathsf{-z=8-3i} \end{array}}\qquad\checkmark$

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3 0

3 years ago

Solve the following integral.<br><br> <img src="https://tex.z-dn.net/?f=%5Cint4x%5Ccos%282-3x%29dx" id="TexFormula1" title="\int

bagirrra123 [75]

Hi there!

$\boxed{-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C}$

To find the indefinite integral, we must integrate by parts.

Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":

u = 4x

du = 4

dv = cos(2 - 3x)

v = 1/3sin(2 - 3x)

Write into the format:

∫udv = uv - ∫vdu

Thus, utilize the solved for expressions above:

4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx

Simplify:

-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx

Integrate the integral:

∫4/3(sin(2 - 3x)dx

u = 2 - 3x

du = -3dx ⇒ -1/3du = dx

-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C

Combine:

$-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C$

7 0

3 years ago

Read 2 more answers

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Harrizon [31]

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