When constructing the histogram, the intervals are selected in such a way that the width of each interval is the same and the gap between two intervals stays uniform throughout the histogram. This makes the data easy to visualize, easy to interpret and easy to understand.
From the given options, option B lists the intervals in an absurd order. First interval is from 0 to 3. There is no gap between first and second interval and the second interval is larger than the first. So these intervals cannot be the set of intervals of a histogram.
So, the answer to this question is option B
Answer:
5/6 = 10/12 and 3/4 = 9/12
Step-by-step explanation:
Find the GCF of the denominators, which is 12.
Answer:
Use the view example tool
Step-by-step explanation:
Use the view example tool and just plug in your number's instead of theirs. I did the same and I got it right.
Answer:
Null Hypothesis, H0 = The pulse rates of men have a standard deviation equal to 10 beats per minute
Alternate Hypothesis, H1 = The pulse rates of men do not have a standard deviation equal to 10 beats per minute
Step-by-step explanation:
The null hypothesis is basically the problem statement i.e
Pulse rates of men have a standard deviation equal to 10 beats per minute
Hence, H0 = The pulse rates of men have a standard deviation equal to 10 beats per minute
The alternate hypothesis will contradict or negate the null hypothesis i.e
H1 = The pulse rates of men do not have a standard deviation equal to 10 beats per minute
Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet, 
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :
Putting all the values,
.....(1)
For maximum height, put
Put t = 1.875 in equation (1)
So, the maximum height reached by the ball is 61.25 m.
