Rate of Change:
At 1 mile in 30 seconds.
At 5 miles in 2.5 minutes. 2.5 minutes = 2.5*60 = 150 seconds.
Rate of change = Change in height / Change in time
= (h₂-h₁)/(t₂-t₁)
= (5 -1) /(150 -30) = 4/120 = (1/30) = 0.0333 miles per second.
= (1/30) miles per second or 0.0333 miles per second.
To have the answer in miles per minute.
(1/30) miles per second = (1/30) miles/second.
60 seconds = 1minute
1 second = (1/60) minute.
(1/30) miles/second = (1/30) miles/(1/60)minute
= (1/30) *60 miles / minute
= 2 miles per minute.
Option C: There are no solutions
Explanation:
The linear equations is graphed.
We need to determine the solution of the system of equations.
The solution of the equations can be determined by finding the point of intersection of the two equations.
From the figure, it is obvious that the two equations are parallel to each other.
Also, the parallel lines have the same slope and the parallel lines never intersect.
Hence, the system consisting of parallel lines have no solution.
Therefore, the solution to the system of linear equations graphed is no solution.
Thus, Option C is the correct answer.
Answer:
Discount = $30, Final price = $90
Step-by-step explanation:
25% is one quarter. 120/4=30
One quarter of 120 is 30, so - 30 would give discounted price of $90.
Similarly you could think of it like the discounted price is 75% of the original one and do 120x0.75=90 to find 75% of 120.
Hope this helped!
Answer:
a) 6.68th percentile
b) 617.5 points
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
a) A student who scored 400 on the Math SAT was at the ______ th percentile of the score distribution.
has a pvalue of 0.0668
So this student is in the 6.68th percentile.
b) To be at the 75th percentile of the distribution, a student needed a score of about ______ points on the Math SAT.
He needs a score of X when Z has a pvalue of 0.75. So X when Z = 0.675.
The digit 3 is in the thousands (1,000) place.
