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SCORPION-xisa [38]
3 years ago
7

How are the molecules moving in a cold glass of water compared to in a warm glass of water

Chemistry
1 answer:
taurus [48]3 years ago
4 0
Molecules move faster in a warm glass of water they move slower in a cold glass of water
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Calculate the mass of sodium azide required to decompose and produce 2.104 moles of nitrogen. Refer to the periodic table to get
Alexxx [7]

91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.

Explanation:

2NaN3======2Na+3N2

This  is the balanced equation for the decomposition and production of sodium azide required to produce nitrogen.

From the equation:

2 moles of NaNO3 will undergo decomposition to produce 3 moles of nitrogen.

In the question moles of nitrogen produced is given as 2.104 moles

so,

From the stoichiometry,

3N2/2NaN3=2.104/x

= 3/2=2.104/x

3x= 2*2.104

   = 1.4 moles

So, 1.4 moles of sodium azide will be required to decompose to produce 2.104 moles of nitrogen.

From the formula

no of moles=mass/atomic mass

        mass=no of moles*atomic mass

                   1.4*65

               = 91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.

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3 years ago
PLEASE HELP TEST density question EASY
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7 0
2 years ago
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Hydrocarbons are compounds that contain
Mademuasel [1]
2) carbon and hydrogen only.
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Which of these would have the largest volume??
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A home solar energy storage unit uses 4.75 ✕ 102 L of water for storing energy. On a sunny day, the water absorbed 2.75 ✕ 104 kJ
Sav [38]

Answer : The water's temperature change will be, 13.85^oC

Explanation : Given,

Density of water = 0.998 g/mL

Volume of water = 4.75\times 10^2L=4.75\times 10^5mL

(conversion used : 1 L = 1000 mL)

Specific heat of water = 4.184J/g^oC

Heat absorbed = 2.75\times 10^4kJ=2.75\times 10^7J

(conversion used : 1 kJ = 1000 J)

First we have to determine the mass of water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

\text{Mass of water}=(0.998g/mL)\times (4.75\times 10^5mL)=474050g

Now we have to calculate the change in temperature of water.

Formula used :

Q=m\times C_w\times \Delta T

where,

Q = heat absorbed by water

m = mass of water

C_w = specific heat of water

\Delta T = change in temperature

Now put all the given value in the above formula, we get:

2.75\times 10^7J=474050g\times 4.184J/g^oC\times \Delta T

\Delta T=13.85^oC

Therefore, the water's temperature change will be, 13.85^oC

8 0
3 years ago
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