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3 years ago

what is the oxidation number for chromium in each of these compounds. show your work. A. K2CrO4 B.Cr2O3

Chemistry

1 answer:

Dmitry [639]3 years ago

7 0

Answer:

A. + 6.

B. + 3.

Explanation:

A. K₂CrO₄:

To calculate the oxidation no. of an element in a compound:

We have that the sum of the oxidation no. of different elements in the compound multiplied by its no. is equal to the overall charge of the compound.

∵ 2(oxidation no. of K) + (oxidation no. of Cr) + 4(oxidation no. of O) = 0.

oxidation no. of K = + 1, oxidation no. of O = - 2.

∴ 2(+ 1) + (oxidation no. of Cr) +4(- 2) = 0.

∴ 2 + (oxidation no. of Cr) - 8 = 0.

∴ (oxidation no. of Cr) - 6 = 0.

∴ oxidation no. of Cr = + 6.

B. Cr₂O₃:

∵ 2(oxidation no. of Cr) + 3(oxidation no. of O) = 0.

oxidation no. of O = - 2.

∴ 2(oxidation no. of Cr) + 3(- 2) = 0.

∴ 2(oxidation no. of Cr) - 6 = 0.

∴ 2(oxidation no. of Cr) = + 6.

∴ (oxidation no. of Cr) = + 6/2 = + 3.

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3 years ago

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The volume of carbon dioxide produced is obtained from the equation below:

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2 years ago

What best describes the bromide ion that forms?

Aloiza [94]

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3 years ago

Help!!! 25 points! REAL ANSWERS ONLY!

Andrei [34K]

Answer:

The answer to your question is:

Explanation:

1) Data

mass = 10 g

vol = 20 ml

density = 10/ 20

= 0.5 g/ml

Data

mass = 5 g

density = 2 g/ml

volume = mass / density

= 5 g / 2

= 2.5 g / ml

Data

density = 25 g/ml

volume = 100 ml

mass = 25 x 100

= 2500 g

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3 years ago