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Katen [24]
2 years ago
6

Part 1. A chemist reacted 18.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat

ion to determine the mass of NaCl that reacted with F2 at 290. K and 1.5 atm.
F2 + 2NaCl → Cl2 + 2NaF

Part 2. Explain how you would determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP.
Chemistry
1 answer:
Daniel [21]2 years ago
6 0

The mass of NaCl that reacted with the F₂ gas at 290 K and 1.5 atm is 132.6 g

<h3>Ideal gas law Equation & Stoichiometry</h3>

From the question, we are to determine the mass of NaCl that reacted with F₂

First, we will determine the number of moles of F₂ that reacted

From the ideal gas law equation, we have that

n = \frac{PV}{RT}

Where n is the number of moles

P is the pressure

V is the volume

R is the gas constant (R = 0.08206 L.atm.mol⁻¹.K⁻¹)

and T is the temperature in Kelvin

From the given information,

V = 18.0 L

T = 290 K

P = 1.5 atm

Putting the parameters into the equation, we get

n = \frac{1.5 \times 18.0}{0.08206\times 290}

n = 1.1346 moles

Now, we will determine the number of moles of NaCl that reacted with this amount of F₂ gas

From the given balaced chemical equation,

F₂ + 2NaCl → Cl₂ + 2NaF

This means, 1 mole of F₂ gas reacts completely with 2 moles of NaCl

Since

1 mole of F₂ gas reacts completely with 2 moles of NaCl

Then,

1.1346 moles of F₂ gas will react completely with 2×1.1346 moles of NaCl

2×1.1346 = 2.2692 moles

This is the number moles of NaCl that reacted

Now, for the mass of NaCl that reacted

From the formula,

Mass = Number of moles × Molar mass

Molar mass of NaCl = 58.44 g/mol

Mass of NaCl that reacted = 2.2692 × 58.44

Mass of NaCl that reacted = 132.6 g

Hence, the mass of NaCl that reacted with the F₂ gas at 290 K and 1.5 atm is 132.6 g

Part 2

To determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP, follow the steps as shown above. But, we will change temperature and pressure to the standard temperature and pressure values. The standard temperature and pressure values are 273.15 K and 1.0 atm respectively.

Afterwards, we will then calculate the mass of sodium chloride needed by using the calculated number of moles and the formula as shown above.

Learn more on Ideal gas law equation & Stoichiometry here: brainly.com/question/15371174

brainly.com/question/8802422

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If you start with 3 moles of sodium and 3 moles of chlorine to produce sodium chloride, what is the limiting reagent?(you will n
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Sodium(Na) is the limiting reagent.

<h3>What is Limiting reagent?</h3>

The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. The precise quantity of reactant required to react with another element may be estimated from the reaction stoichiometry.

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What volume of a 0.550 M solution of potassium hydroxide (KOH) can be made with 19.9 g of potassium hydroxide?
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Answer:

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Explanation:

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(Step 1)

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(Step 2)

Molarity = moles / volume                            <----- Molarity ratio

0.550 M = 0.355 moles / volume                 <----- Insert values

(0.550 M) x volume = 0.355 moles              <----- Multiply both sides by volume

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