Answer:
1
Explanation:
1 is the answer Mn^2+ is oxidized to Mn.
Overall loss in electon = 2-1=1
The answer should be; 11
The atomic mass number is found by combining the number of protons and neutrons
Hope this helps :)
Answer:
V₂ = 1592.32 L
Explanation:
Given data:
Initial number of moles = 1.54 mol
Initial volume = 383.2 L
Final volume = ?
Final number of moles = 6.4 mol
Solution:
Formula:
V₁/n₁ = V₂/n₂
V₁ = Initial volume
n₁ = initial number of moles
V₂ = Final volume
n₂ = Final number of moles
now we will put the values in formula.
V₁/n₁ = V₂/n₂
383.2 L / 1.54 mol = V₂/ 6.4 mol
V₂ = 248.8 L/mol ×6.4 mol
V₂ = 1592.32 L
Answer:
Kindly check the explanation section.
Explanation:
From the description given in the question above, that is '' H subscript f to the power of degree of the reaction" we have that the description matches what is known as the heat of formation of the reaction, ∆fH° where the 'f' is a subscript.
In order to determine the heat of formation of any of the species in the reaction, the heat of formation of the other species must be known and the value for the heat of reaction, ∆H(rxn) must also be known. Thus, heat of formation can be calculated by using the formula below;
∆H(rxn) = ∆fH°( products) - ∆fH°(reactants).
That is the heat of formation of products minus the heat of formation of the reaction g specie(s).
Say heat of formation for the species is known as N(g) = 472.435kj/mol, O(g) = 0kj/mol and NO = unknown, ∆H°(rxn) = −382.185 kj/mol.
−382.185 = x - 472.435kj/mol = 90.25 kJ/mol