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3 years ago

What are some remarkable properties of water

Chemistry

1 answer:

frosja888 [35]3 years ago

7 0

Explanation:

Water can dissolve in many things because of it's polarity and surface tension.
Water is the only substance that is lighter in its solid form.

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Balance the following reactions using either the oxidation number method or the half-reaction method. Identify which element has

Marina86 [1]

$6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO_3^- + 3H_2O$ is the balanced chemical equation.

<h3>What is a balanced chemical equation?</h3>

A balanced chemical reaction is an equation that has equal numbers of each type of atom on both sides of the arrow.

Half-reaction method:

Unbalanced chemical equation:

$Ce^{4+} + I^-$ → $Ce^{3+} + IO^{3-}$

Oxidation half-reaction:

$I^-+ 6OH^- - 6e-$ → I $O^{3-} + 3H_2O$

Reduction half-reaction:

$Ce4^+ + e^-$ → $Ce^{3+}$

Balanced chemical equation:

$6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO^{3-} + 3H_2O$

Oxidation number method:

Unbalanced chemical equation:

$Ce^{4+} + I^-$ → $Ce^{3+} + IO^{3-}$

$I^{-1} -6e^-$ → $I^{+5}$

$Ce^{4+} + e^-$ → $Ce^{3+}$

Balanced chemical equation:

$6Ce^{4+} + I^{-1}$ → $6Ce^{3+} + I^{+5}$

$6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO_3^- + 3H_2O$

Hence, $6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO_3^- + 3H_2O$ is the balanced chemical equation.

Learn more about the balanced chemical equation here:

https://brainly.in/question/46754758

#SPJ1

6 0

2 years ago

What volume, in milliliters, of a 0.140 M solution of KCl contains 2.65 g of the compound?

marishachu [46]

Answer:

Calculate moles KCl: 2.55 g / 74.55 g/mol = 0.0342 moles KCl

Volume KCl = 0.0342 mol X (1 L/0.150 mol) = 0.228 L X 1000 mL/L = 228 mL

Explanation:

3 0

3 years ago

Can two different samples of the same substance have different physical properties? Chemical properties?

lina2011 [118]

yes, because they are combined in different ratios.

4 0

3 years ago

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Based on the oxidation states of the atoms in this reaction, answer the questions. Fe(0) + O2(0) → Fe2(3+)O3(2-) How many electr

Oliga [24]

Half reaction 1: 2Fe° → Fe₂³⁺ + 6e⁻ /×2.
4Fe° → 2Fe₂³⁺ + 12e⁻.
Iron is oxidized from neutral charge (0) to oxidation number +3, one iron lose three electrons, two irons lose six electrons and four irons twelve electrons.
Half reaction 2: 12e⁻ + 3O₂ → 2O₃²⁻
Oxygen is reduced from neutral chage to oxidation number -2, one oxygen gain two electrons, six oxygens gain twelve electrons.
Balanced chemical reaction: 4Fe + 3O₂ → 2Fe₂O₃.

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3 years ago

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Hey Google please how what types of elements are crop in P block right with example

Arte-miy333 [17]

Explanation:

you can google it but if you can't get I will ask my teacher and write the full question

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3 years ago

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