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BigorU [14]
3 years ago
10

Jethro wants a swimming pool in his backyard, so he digs a rectangular hole with dimensions 40 feet long, 20 feet wide, and 5 fe

et deep. How many cubic feet of water will the pool hold?
A) 65 cubic feet of water B) 8000 cubic feet of water C) 4000 cubic feet of water D) 40,000 cubic feet of water
Mathematics
2 answers:
Goshia [24]3 years ago
5 0
First find the perimeter. Then take the depth of the pool and multiply it by the perimeter.
Hope this helps
Marina CMI [18]3 years ago
3 0
C) 4,000 cubic feet of water
Reason: 40x20x5
40x20=800
800x5=4,000
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5/6-1/8 Solve by finding a common denominator<br><br> A)30/48<br> B)34/48<br> C)38/48<br> D)42/48
GrogVix [38]

Answer:

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The easiest common denominator to find is the product of the denominators you have.

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The difference is ...

  \dfrac{5}{6}-\dfrac{1}{8}=\dfrac{5}{6}\cdot\dfrac{8}{8}-\dfrac{1}{8}\cdot\dfrac{6}{6}\\\\=\dfrac{40-6}{48}=\boxed{\dfrac{34}{48}}

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<em>Additional comment</em>

The difference numerator and denominator have a common factor of 2, so can be reduced to 17/24. The denominator 24 could have been used as the common denominator from the start.

  5/6 -1/8 = 20/24 -3/24 = 17/24 . . . . reduced result

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