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Maurinko [17]
3 years ago
10

Three-fourths of the area of a rectangular lawn 30 feet wide by 40 feet long is to be enclosed by a rectangular fence. If the en

closure has full width and reduced length rather than full length and reduced width, how much less fence will be needed
Physics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

The fence is 5feet less.

Explanation:

We need to determine

The less amount of fence required, if the enclosure has full width and reduced length, compared to full length and reduced width.

Approach & WorkingArea of lawn = 30 × 403/4th of the area of lawn = ¾(30 × 40) = 30 * 30

 When full width will be fenced, and reduced length will be fenced.

Width = 30 feet30 * L = 30 * 30Hence, length = 30 feetLength of fence needed = 2(30 + 30) = 120 feet

When full length will be fenced, and reduced width will be fenced

Length = 40 feet40 * W = 30 * 30W = 22.5 feetLength of fence needed = 2(40 + 22.5) = 125 feet

Difference in length of fence needed = 125 – 120 = 5 feet.

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6 0
2 years ago
On a drive from one city to? another, victor averaged 39 mph. if he had been able to average 72 ?mph, he would have reached his
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Let the unknown distance be xmiles
x/39-x/72=11hr
72x-39x/2808=11hr
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33x= 30888
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U can substitue back to check
at speed of 72mph, he would need 936/72=13hrs
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the difference is 24-13=11
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2 years ago
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