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3 years ago

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Three-fourths of the area of a rectangular lawn 30 feet wide by 40 feet long is to be enclosed by a rectangular fence. If the en

closure has full width and reduced length rather than full length and reduced width, how much less fence will be needed

1 answer:

satela [25.4K]3 years ago

4 0

Answer:

The fence is 5feet less.

Explanation:

We need to determine

The less amount of fence required, if the enclosure has full width and reduced length, compared to full length and reduced width.

Approach & WorkingArea of lawn = 30 × 403/4th of the area of lawn = ¾(30 × 40) = 30 * 30

When full width will be fenced, and reduced length will be fenced.

Width = 30 feet30 * L = 30 * 30Hence, length = 30 feetLength of fence needed = 2(30 + 30) = 120 feet

When full length will be fenced, and reduced width will be fenced

Length = 40 feet40 * W = 30 * 30W = 22.5 feetLength of fence needed = 2(40 + 22.5) = 125 feet

Difference in length of fence needed = 125 – 120 = 5 feet.

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Arte-miy333 [17]

Answer with Explanation:

We are given that

Initial speed= $u=19 m/s$

a. $g=9.8m/s^2$

Final velocity of ball= $v=0$

$v=u-gt$

g is negative because the ball is going against to gravity.

$0=19-9.8t$

$9.8t=19$

$t=\frac{19}{9.8}=1.94 s$

$s=ut-\frac{1}{2}gt^2$

Using the formula

$s=19(1.94)-\frac{1}{2}(9.8)(1.94)^2$

$s=18.4 m$

a.The ball rise upto height 18.4 m

b.It take 1.94 s to reach its highest point.

c.Initial velocity=0,s=18.4 m

$s=ut+\frac{1}{2}gt^2$

$18.4=0(t)+\frac{1}{2}(9.8)t^2$

$18.4=4.9t^2$

$t^2=\frac{18.4}{4.9}$

$t=\sqrt{\frac{18.4}{4.9}}$

$t=1.94 s$

$v=u+gt$

Using the formula

$v=0+9.8(1.94)=19 m/s$

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3 years ago

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Paraphin [41]

Answer:

$F=mg$

Explanation:

Close to Earth's surface, the force of gravity that pulls an object towards the ground is

$F=mg$ (2)

where

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This is an approximation of the general formula of gravity valid only close to Earth's surface. The more general formula is

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At the Earth's surface,

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soldi70 [24.7K]

The correct answer is
<span>force per unit charge.

In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span> $E= \frac{F}{q}$
where
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Ber [7]

Answer:

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Explanation:

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Generally the emf induced is mathematically represented as

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Here $\Delta t$ is the time taken

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dolphi86 [110]

Answer:

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Explanation:

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